我有两张桌子,我想:

1.-从表“A”中选择每个‘id_user’的计数:
查询:
SELECT COUNT(*), user.user_name as user_name
FROM A
INNER JOIN user
ON A.ID_user = user.ID_USER
GROUP BY ID_user;结果:

2.-从表"B"中选择每个'id_user‘的值分数
查询:
SELECT SCORE, user.user_name as user_name
FROM B
INNER JOIN user
ON B.id_user = user.id_user_name
GROUP BY id_user;结果:

3.-将这两个值相加,并显示按用户名分组的总分:
我的预期产出将是这样的,包括表A和表B的分数之和:
预期产出:

发布于 2021-01-04 20:03:52
这是你想要的吗?
select u.*,
(select sum(a.score) from a where a.id_user = u.id_user) as a_sum,
(select sum(b.score) from b where b.id_user = u.id_user) as b_sum
from user u;如果您想要总分,只需将它们加在一起:
select u.*,
( (select COUNT(1) from a where a.id_user = u.id_user) +
(select coalesce(sum(b.score), 0) from b where b.id_user = u.id_user)
) as ab_sum
from user u;https://stackoverflow.com/questions/65569079
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