我正在尝试实现一个OAuth流,在我的客户服务中,我有以下代码行:
services.AddAuthentication(config => {
// We check the cookie to confirm that we are authenticated
config.DefaultAuthenticateScheme = "ClientCookie";
// When we sign in we will deal out a cookie
config.DefaultSignInScheme = "ClientCookie";
// use this to check if we are allowed to do something.
config.DefaultChallengeScheme = "OurServer";
})
.AddCookie("ClientCookie")
.AddOAuth("OurServer", config => {
config.ClientId = "client_id";
config.ClientSecret = "client_secret";
config.CallbackPath = "/oauth/callback";
config.AuthorizationEndpoint = "https://localhost:44360/oauth/authorize";
config.TokenEndpoint = "https://localhost:44360/oauth/token";
config.SaveTokens = true;
config.Events = new OAuthEvents()
{
OnCreatingTicket = context =>
{
var accessToken = context.AccessToken;
var base64payload = accessToken.Split('.')[1];
var modified = base64payload.Replace(" ", "");
var bytes = Convert.FromBase64String(base64payload);
var jsonPayload = Encoding.UTF8.GetString(bytes);
var claims = JsonConvert.DeserializeObject<Dictionary<string, string>>(jsonPayload);
foreach (var claim in claims)
{
context.Identity.AddClaim(new Claim(claim.Key, claim.Value));
}
return Task.CompletedTask;
}
};
});当它尝试从其base64表示转换字符串时,它将抛出一个:System.FormatException: The input is not a valid Base-64 string as it contains a non-base 64 character, more than two padding characters, or an illegal character among the padding characters.
这让我感到困惑,因为我正在学习一个关于YouTube的教程,据我所知,从跟踪它和查看github代码就可以看出它是相同的。假定无效的Base64字符串是:
eyJzdWIiOiJzb21lX2lkIiwiR3Jhbm55IjoiQ29va2llIiwibmJmIjoxNjEwMTYwMjE5LCJleHAiOjE2MTAyNDY2MTksImlzcyI6Imh0dHA6Ly9sb2NhbGhvc3Q6NDQzNjAvIiwiYXVkIjoiaHR0cDovL2xvY2FsaG9zdDo0NDM2MC8ifQ这很奇怪,因为在https://www.base64decode.org/上正确地检查它会返回以下内容:
{"sub":"some_id","Granny":"Cookie","nbf":1610160219,"exp":1610246619,"iss":"http://localhost:44360/","aud":"http://localhost:44360/"}它似乎是有效的,因为它与我在服务器端的控制器中设置的JWT令牌的声明和内容匹配。我到底做错了什么?我检查了处理令牌问题的其他地方,但没有看到任何无效字符,如-、+等。
编辑:
它的修复方法是执行以下操作,这要感谢LinkedListT提到它不是一个倍数a 4。
private string AddPaddingToBase64(string base64)
{
if(base64.Length % 4 == 0)
return base64;
else
{
var builder = new StringBuilder(base64);
builder.Append("=");
return AddPaddingToBase64(builder.ToString());
}
}然后,我们首先解析字符串,让它通过该方法,然后将修改后的base64传递给转换器。这也是在3+专业开发年中,递归实际上比迭代更简单、更直接的第一次。
发布于 2021-01-09 03:07:19
问题是您的base64字符串无效。
一个base64编码字符串的长度总是4的倍数。如果它不是4的倍数,那么=字符被追加直到它是。当值包含=字符时,表单?name=value的查询字符串出现问题(其中一些字符将被删除,我不记得确切的行为)。在执行base64解码之前,您可能可以附加正确的=字符数。https://stackoverflow.com/a/2925959/9936356
因此,您需要将'==‘附加到base64字符串中。也就是说。
Convert.FromBase64String("eyJzdWIiOiJzb21lX2lkIiwiR3Jhbm55IjoiQ29va2llIiwibmJmIjoxNjEwMTYwMjE5LCJleHAiOjE2MTAyNDY2MTksImlzcyI6Imh0dHA6Ly9sb2NhbGhvc3Q6NDQzNjAvIiwiYXVkIjoiaHR0cDovL2xvY2FsaG9zdDo0NDM2MC8ifQ==");https://stackoverflow.com/questions/65638895
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