每三个单词拆分一次文件&创建三重奏列表

Question

我有一个txt文件，其中包含我用Python导入的文本，我希望每隔3个单词将它分开。

例如,

Python is an interpreted, high-level and general-purpose programming language

我想成为，

[['Python', 'is', 'an'],['interpreted,', 'high-level','and'],['general-purpose','programming','language']].

到目前为止我的代码，

lines = [word.split() for word in open(r"c:\\python\4_TRIPLETS\Sample.txt", "r")]
print(lines)

给我这个输出，

[['Python', 'is', 'an', 'interpreted,', 'high-level', 'and', 'general-purpose', 'programming', 'language.', "Python's", 'design', 'philosophy', 'emphasizes', 'code', 'readability', 'with', 'its', 'notable', 'use', 'of', 'significant', 'whitespace.', 'Its', 'language', 'constructs', 'and', 'object-oriented', 'approach', 'aim', 'to', 'help', 'programmers', 'write', 'clear,', 'logical', 'code', 'for', 'small', 'and', 'large-scale', 'projects.']]

有什么想法吗？

Answer 1

使用列表理解将列表转换为n项的块

with open('c:\\python\4_TRIPLETS\Sample.txt', 'r') as file:
    data = file.read().replace('\n', '').split()
    lines = [data[i:i + 3] for i in range(0, len(data), 3)]
    print(lines)

Answer 2

您可以使用一个拆分字符串来分隔每个单词，然后遍历列表并将它们分组成对三个单词。

   final =  = [None] * math.ceil(lines/3)
   temp = [None] * 3
   i = 0
   for x in lines:
      if(i % 3 == 0)
         final.append(temp)
         temp = [None] * 3
      temp.append(x)