我在0中看不到值的套接字类型
socket_type.h
/* Types of sockets. */
enum __socket_type
{
SOCK_STREAM = 1, /* Sequenced, reliable, connection-based
byte streams. */
#define SOCK_STREAM SOCK_STREAM
SOCK_DGRAM = 2, /* Connectionless, unreliable datagrams
of fixed maximum length. */
#define SOCK_DGRAM SOCK_DGRAM
SOCK_RAW = 3, /* Raw protocol interface. */
#define SOCK_RAW SOCK_RAW
SOCK_RDM = 4, /* Reliably-delivered messages. */
#define SOCK_RDM SOCK_RDM
SOCK_SEQPACKET = 5, /* Sequenced, reliable, connection-based,
datagrams of fixed maximum length. */
#define SOCK_SEQPACKET SOCK_SEQPACKET
SOCK_DCCP = 6, /* Datagram Congestion Control Protocol. */
#define SOCK_DCCP SOCK_DCCP
SOCK_PACKET = 10, /* Linux specific way of getting packets
at the dev level. For writing rarp and
other similar things on the user level. */
#define SOCK_PACKET SOCK_PACKET
/* Flags to be ORed into the type parameter of socket and socketpair and
used for the flags parameter of paccept. */
SOCK_CLOEXEC = 02000000, /* Atomically set close-on-exec flag for the
new descriptor(s). */
#define SOCK_CLOEXEC SOCK_CLOEXEC
SOCK_NONBLOCK = 00004000 /* Atomically mark descriptor(s) as
non-blocking. */
#define SOCK_NONBLOCK SOCK_NONBLOCK
};但是,如果我没有指定addrinfo struct字段ai_socktype,怎么办?值是0,当__socktype_type中没有这类类型时,该类型是哪种类型?
发布于 2021-01-24 16:44:20
将0用于ai_socktype意味着“任意类型”。
从手册页到getaddrinfo
The hints argument points to an addrinfo structure that specifies
criteria for selecting the socket address structures returned in
the list pointed to by res. If hints is not NULL it points to an
addrinfo structure whose ai_family, ai_socktype, and ai_protocol
specify criteria that limit the set of socket addresses returned
by getaddrinfo(), as follows:
[...]
ai_socktype
This field specifies the preferred socket type, for
example SOCK_STREAM or SOCK_DGRAM. Specifying 0 in this
field indicates that socket addresses of any type can be
returned by getaddrinfo().“在此字段中指定0表示getaddrinfo()可以返回任何类型的套接字地址。”
https://stackoverflow.com/questions/65873180
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