如何使用django-graphql自定义错误？

Question

我正在使用Django和Graphene进行一个项目，使用django_graphql_auth库来处理身份验证，并要求我自定义在登录失败时收到的错误消息。我已经仔细阅读了文档如何做到这一点，它只提到了一个名为CUSTOM_ERROR_TYPE( 类型 )的设置，但我想我不知道如何使用它，或者它可能不像我想的那样工作。在我的档案里：

custom_errors.py

import graphene

class CustomErrorType(graphene.Scalar):
    @staticmethod
    def serialize(errors):
        return {"my_custom_error_format"}

settings.py

from .custom_errors import CustomErrorType

GRAPHQL_AUTH = {
    'CUSTOM_ERROR_TYPE': CustomErrorType,
}

user.py

class AuthRelayMutation(graphene.ObjectType):
    password_set = PasswordSet.Field()
    password_change = PasswordChange.Field()

    # # django-graphql-jwt inheritances
    token_auth = ObtainJSONWebToken.Field()
    verify_token = relay.VerifyToken.Field()
    refresh_token = relay.RefreshToken.Field()
    revoke_token = relay.RevokeToken.Field()
    unlock_user = UsuarioUnlock.Field()

class Mutation(AuthRelayMutation, graphene.ObjectType):
    user_create = UserCreate.Field()
    user_update = UserUpdate.Field()
    user_delete = UserDelete.Field()

schema = graphene.Schema(query=Query, mutation=Mutation)

然而，当我测试登录时，我仍然收到这样的消息：“请输入有效的凭据。”我该怎么做才能改变这个信息？

更新

class ObtainJSONWebToken(
    RelayMutationMixin, ObtainJSONWebTokenMixin, graphql_jwt.relay.JSONWebTokenMutation
):
    __doc__ = ObtainJSONWebTokenMixin.__doc__
    user = graphene.Field(UserNode)
    days_remaining = graphene.Field(graphene.String, to=graphene.String())
    unarchiving = graphene.Boolean(default_value=False)

    @classmethod
    def resolve(cls, root, info, **kwargs):
        user = info.context.user

        # Little logic validations

        unarchiving = kwargs.get("unarchiving", False)
        return cls(user=info.context.user, days_remaining=days_remaining)
        

    @classmethod
    def Field(cls, *args, **kwargs):
        cls._meta.arguments["input"]._meta.fields.update(
            {"password": graphene.InputField(graphene.String, required=True)}
        )
        for field in app_settings.LOGIN_ALLOWED_FIELDS:
            cls._meta.arguments["input"]._meta.fields.update(
                {field: graphene.InputField(graphene.String)}
            )
        return super(graphql_jwt.relay.JSONWebTokenMutation, cls).Field(*args, **kwargs)

Answer 1

我也有过同样的问题。我找到并引用了这个GitHub线程：https://github.com/flavors/django-graphql-jwt/issues/147 --它有点过时了，但是我对它进行了调整，它起了作用：

import graphql_jwt
from graphql_jwt.exceptions import JSONWebTokenError


class CustomObtainJSONWebToken(ObtainJSONWebToken):
    @classmethod
    def mutate(cls, *args, **kwargs):
        try:
            return super().mutate(*args, **kwargs)
        except JSONWebTokenError:
            raise Exception('Your custom error message here')

Answer 2

我也遇到了这个问题，但是由于这条线在graphql_auth/bases.py的django-graphql-auth库中，您必须将settings.py文件中的类指定为字符串，以便使用自定义错误。这似乎解决了我的问题。

例如，我有：

GRAPHQL_AUTH = {
    'CUSTOM_ERROR_TYPE': 'accounts.custom_errors.CustomErrorType'
}

(其中CustomErrorType是一个类似于您在最初的文章中指出的类)

Answer 3

通过使用ErrorType提供的graphene_django错误格式，我修改了上面的代码。

import graphene
import graphql_jwt

from ..types import UserType
from graphene_django.types import ErrorType

from graphql_jwt.exceptions import JSONWebTokenError
from graphql_jwt.mixins import ResolveMixin

class CreateToken(graphql_jwt.JSONWebTokenMutation, ResolveMixin):
    user = graphene.Field(UserType)
    errors = graphene.List(ErrorType)

    @classmethod
    def mutate(cls, *args, **kwargs):
        try:
            return super().mutate(*args, **kwargs)
        except JSONWebTokenError as e:
            errors = ErrorType.from_errors({'username/password': [str(e)]})
            return cls(errors=errors)

    
    @classmethod
    def resolve(cls, root, info, **kwargs):
        return cls(user=info.context.user, errors=[])