获取'name‘是一个无效的关键字参数(使用graphene-django)

Question

我正在使用石墨烯，获取'name‘是GuestMutation错误的无效关键字参数，它与什么相关？

//models.py

class Guest(models.Model):
    name = models.CharField(max_length=100)
    phone = models.IntegerField()

    def __str__(self):
        return self.name



//schema.py
class GuestType(DjangoObjectType):
    class Meta:
        model = Guest
        fields = ('id','name','phone')
        
        
class GuestMutation (graphene.Mutation):

    class Arguments:
        name = graphene.String(required=True)
        phone = graphene.Int(required=True)

    guest = graphene.Field(GuestType)

    @classmethod
    def mutate(cls, root,info,name,phone):
        guest = Guest(name=name, phone=phone)
        guest.save()
        return GuestMutation(name=name, phone=phone)

class Mutation(graphene.ObjectType):

    add_guest = GuestMutation.Field()

错误信息

回溯(最近一次调用)：文件"/home/ahmed/Documents/Django/Shalleh/my-project-env/lib/python3.8/site-packages/promise/promise.py"，行489，在_resolve_from_executor执行器(解析，拒绝)文件"/home/ahmed/Documents/Django/Shalleh/my-project-env/lib/python3.8/site-packages/promise/promise.py"，行756中，在执行器返回解析(f(*args)，**kwargs))文件"/home/ahmed/Documents/Django/Shalleh/my-project-env/lib/python3.8/site-packages/graphql/execution/middleware.py"，第75行，在make_it_promise返回next(*args，**kwargs)文件"/home/ahmed/Documents/Django/Shalleh/booking/schema.py"，第66行，在变异返回GuestMutation(name=name，文件"/home/ahmed/Documents/Django/Shalleh/my-project-env/lib/python3.8/site-packages/graphene/types/objecttype.py"，第169行，在init raise ( graphql.error.located_error.GraphQLLocatedError：'name‘)中，GuestMutation的关键字参数无效。

Answer 1

你正在返回错误的信息：

class GuestMutation (graphene.Mutation):
    # What you accept as input
    class Arguments:
        name = graphene.String(required=True)
        phone = graphene.Int(required=True)

    # What you return as output
    guest = graphene.Field(GuestType)

因此，如前所述，您需要返回您创建的来宾。