如何检查子数组是否包含另一个数组javascript的所有元素

Question

我有一个名为rawProjects的项目数组，如下所示：

rawProjects = [
    {
         id: 1,
         name: "proj1",
         technology: [
             0: {id: 21, project_id: 1,name: "java"},
             1: {id: 22, project_id: 1,name: "c++"}
          ]
    },
    {
         id: 2,
         name: "proj2",
         technology: [
             0: {id: 23, project_id: 2,name: "sql"},
             1: {id: 24, project_id: 2,name: "python"},
             2: {id: 25, project_id: 2,name: "react"}

         ]
    }
]

我还有一个名为tempTags的技术数组，它包含用户进入搜索的技术。到目前为止，我已经能够在OR的情况下返回包含用户提到的任何一种技术的项目，使用：

const filteredProjects = rawProjects.filter(x => x.technology.some(g => tempArr.includes(g.name)))

因此，例如，如果tempTags = [sql, c++]将返回两个项目。

如何实现AND案例，以便只返回包含这两种技术的项目。如果是tempTags = [java, c++]，只会返回第一个项目。如果是tempTags = [sql, c++]，什么都不会返回？

Answer 1

遍历tempTags并检查其中一个.every是否包括：

​

const rawProjects = [
    {
         id: 1,
         name: "proj1",
         technology: [
             {id: 21, project_id: 1,name: "java"},
             {id: 22, project_id: 1,name: "c++"}
          ]
    },
    {
         id: 2,
         name: "proj2",
         technology: [
             {id: 23, project_id: 2,name: "sql"},
             {id: 24, project_id: 2,name: "python"},
             {id: 25, project_id: 2,name: "react"}

         ]
    }
]

const tempTags = ['java', 'c++'];
const filtered = rawProjects.filter(
  p => {
    const techNames = p.technology.map(({ name }) => name);
    return tempTags.every(
      tag => techNames.includes(tag)
    );
  }
);
console.log(filtered);

​

您还需要修复语法:数组没有键值对，只有值。(删除0:、1:等)，并确保在数组值之间放置逗号(在"python"}之后应该有逗号)