如何简化这个首字母缩写生成器？

Question

我写了首字母缩写生成器的代码。我只能让它工作十个字。

我觉得代码是不必要的重复。有更简单的方法吗？它能对一组更大的词起作用吗？

我刚开始编码，我对编程一无所知，所以我可能需要在你的答案中详细解释。

userInput = input('enter name of the organization not more than ten words: ')
listInput = userInput.split()


if len(listInput) == 1:
    a = listInput[0]
    acronym = a[0]
    print(acronym.upper())
elif len(listInput) == 2:
    a = listInput[0]
    b = listInput[1]
    acronym = a[0] + b[0]
    print(acronym.upper())
elif len(listInput) == 3:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    acronym = a[0] + b[0] + c[0]
    print(acronym.upper())
elif len(listInput) == 4:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    acronym = a[0] + b[0] + c[0] + d[0]
    print(acronym.upper())
elif len(listInput) == 5:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    e = listInput[4]
    acronym = a[0] + b[0] + c[0] + d[0] + e[0]
    print(acronym.upper())
elif len(listInput) == 6:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    e = listInput[4]
    f = listInput[5]
    acronym = a[0] + b[0] + c[0] + d[0] + e[0] + f[0]
    print(acronym.upper())
elif len(listInput) == 7:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    e = listInput[4]
    f = listInput[5]
    g = listInput[6]
    acronym = a[0] + b[0] + c[0] + d[0] + e[0] + f[0] + g[0]
    print(acronym.upper())
elif len(listInput) == 8:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    e = listInput[4]
    f = listInput[5]
    g = listInput[6]
    h = listInput[7]
    acronym = a[0] + b[0] + c[0] + d[0] + e[0] + f[0] + g[0] + h[0]
    print(acronym.upper())
elif len(listInput) == 9:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    e = listInput[4]
    f = listInput[5]
    g = listInput[6]
    h = listInput[7]
    i = listInput[8]
    acronym = a[0] + b[0] + c[0] + d[0] + e[0] + f[0] + g[0] + h[0] + i[0]
    print(acronym.upper())
else:
    a = listInput[0]
    b = listInput[1]
    c = listInput[2]
    d = listInput[3]
    e = listInput[4]
    f = listInput[5]
    g = listInput[6]
    h = listInput[7]
    i = listInput[8]
    j = listInput[9]
    acronym = a[0] + b[0] + c[0] + d[0] + e[0] + f[0] + g[0] + h[0] + i[0] + j[0]
    print(acronym.upper())

Answer 1

使用循环、生成器表达式或理解来处理动态长度数据：

userInput = input('enter name of the organization not more than ten words: ')
listInput = userInput.split()

acro = ''.join(token[0].upper() for token in listInput)
print(acro)

这使用带有生成器表达式的str.join将首字母组合成单个字符串。