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链式strsep给出了分割错误-C
EN

Stack Overflow用户
提问于 2021-03-10 14:43:55
回答 1查看 85关注 0票数 1

我正在尝试创建一个字符串数组,以准备将它们显示在表中。

因此,我有一个函数,返回一个缓冲区字符串,其中包含一些扫描的wifi访问点的列表,我使用strsep将其拆分为"\n",然后再由"\t"拆分。

循环运行良好,直到结束为止,当计算while参数((line = strsep(&buf, "\n")))时,它会给出一个SEGFAULT

per @Jabberwocky的简短示例:

代码语言:javascript
复制
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

static int
wap_scan_count_lines(char*      wap_scan)
{
    int   line_amount = 0;
    char *scan = wap_scan;

    while(*scan)
    {
        if ('\n' == *scan){
            line_amount++;
        }
        scan++;
    }
    return line_amount;
}

int main() {

    char ***scan_result, *line=NULL, *item=NULL, *scan=NULL;
    scan = strdup("bssid / frequency / signal level / flags / ssid\n"
                  "a8:6a:bb:e2:d6:ef       5785    -47     [WPA-PSK-CCMP+TKIP][WPA2-PSK-CCMP+TKIP][WPS][ESS]       Fibertel WiFi114 5.8GHz");
    int wap_scan_size = wap_scan_count_lines(scan);
    scan_result = malloc(wap_scan_size * sizeof(**scan_result));
    int i = 0;
    int item_len = sizeof (*scan_result);

    while((line = strsep(&scan, "\n")) != NULL ) {
        if(i==0){
            i++;
            continue;
        }
        char **scan_line = calloc(5, item_len);
        int j = 0;
        while ((item = strsep(&line, "\t")) != NULL) {
            printf("%s\n", item);
            scan_line[j++] = strdup(item);
        }
        scan_result[i++] = scan_line;
    }
    return 0;
}

真正的功能给了我这个问题:

代码语言:javascript
复制
char *** wifi_client_get_wap_list(int *len)
{
    char ***scan_result;
    char *buf, *buf_free, *cmd, *line, *item;
    int ret, items_len;
    cmd = strdup("SCAN");
    ret = wpa_ctrl_command(cmd, NULL);
    if (ret < 0) goto error;

    cmd = strdup("SCAN_RESULTS");
    ret = wpa_ctrl_command(cmd, &buf); //RETURNS A STRING ON BUF ALLOCATED BY STRDUP
    if (ret < 0){
        free(buf);
        goto error;
    }

    *len = wap_scan_count_lines(buf); //NUMBER OF LINES IN THE SCAN RESULT
    scan_result = calloc(*len, sizeof(**scan_result));
    int i = 0, j;
    buf_free = buf;
    items_len = sizeof (*scan_result);

    while ((line = strsep(&buf, "\n"))){ //THIS GIVES THE SEGFAULT AT THE END
        // SKIP FIRST LINE WITH HEADERS
        if (i==0){
            i++;
            continue;
        }

        //if (strcmp(line, "") == 0) {
        //  break;   
        //}

       //EACH LINE HAS 5 VALUES (bssid, freq, level,flags,ssid)
        char **scan_line = calloc(5, items_len); 
        j = 0;
        printf("INNER STEPS:\n");
        while((item = strsep(&line, "\t"))){
            *(scan_line + j) = strdup(item);
            printf("%d ", j);
            j++;
        }
        *(scan_result + i) = scan_line;
        printf("\nSTEP: %d\n", i);
        i++;
    }

    free(buf_free);
    free(cmd);
    return scan_result;

    error:
    // @TODO: Handle error
    if (ret == -2) {
        printf("'%s' command timed out.\n", cmd);
    } else if (ret < 0) {
        printf("'%s' command failed.\n", cmd);
    }

    free(cmd);
    return NULL;
}
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2021-03-11 00:37:28

基于https://man7.org/linux/man-pages/man3/strsep.3.html,问题是循环将比您希望的多运行一次,从而导致scan_result溢出。

文件的有关部分如下:

代码语言:javascript
复制
   The strsep() function returns a pointer to the token, that is, it
   returns the original value of *stringp.

代码语言:javascript
复制
   If *stringp is NULL, the strsep() function returns NULL and does
   nothing else.  Otherwise, this function finds the first token in
   the string *stringp, that is delimited by one of the bytes in the
   string delim.  This token is terminated by overwriting the
   delimiter with a null byte ('\0'), and *stringp is updated to
   point past the token.  In case no delimiter was found, the token
   is taken to be the entire string *stringp, and *stringp is made
   NULL.

wap_scan_count_lines中,计算以'\n‘结尾的行数。

在下面的2行中,根据以'\n‘结尾的行数分配内存以保存结果。

代码语言:javascript
复制
int wap_scan_size = wap_scan_count_lines(scan);
scan_result = malloc(wap_scan_size * sizeof(**scan_result));

但是,上述引用的 strsep ()文档意味着,在您的简化示例中,调用第一个乘以strsep,在调用结束时,结果将不是NULL,而扫描在调用期间不会设置为NULL。下一次通过调用,扫描将在调用期间设置为NULL,但结果不会为NULL。这意味着循环的主体将执行wap_scan_size +1次,从而导致scan_result.结束后的写入。

至少有两个可能的修复,取决于您是否真的想要处理输入末尾没有被'\n‘终止的任何行。

如果您确实需要处理这些行,这对我来说似乎更健壮,特别是考虑到简化的示例以这样的行结尾,那么只需在scan_result中分配一个额外的条目即可。

代码语言:javascript
复制
scan_result = malloc((wap_scan_size + 1) * sizeof(**scan_result));

如果您确信不需要处理这些行,但这在我看来是不正确的,请更改:

代码语言:javascript
复制
while((line = strsep(&scan, "\n")) != NULL ) {

代码语言:javascript
复制
for(line = strsep(&scan, "\n"); scan != NULL; line = strsep(&scan, "\n") ) {
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/66567040

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