我正在尝试创建一个字符串数组,以准备将它们显示在表中。
因此,我有一个函数,返回一个缓冲区字符串,其中包含一些扫描的wifi访问点的列表,我使用strsep将其拆分为"\n",然后再由"\t"拆分。
循环运行良好,直到结束为止,当计算while参数((line = strsep(&buf, "\n")))时,它会给出一个SEGFAULT。
per @Jabberwocky的简短示例:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
static int
wap_scan_count_lines(char* wap_scan)
{
int line_amount = 0;
char *scan = wap_scan;
while(*scan)
{
if ('\n' == *scan){
line_amount++;
}
scan++;
}
return line_amount;
}
int main() {
char ***scan_result, *line=NULL, *item=NULL, *scan=NULL;
scan = strdup("bssid / frequency / signal level / flags / ssid\n"
"a8:6a:bb:e2:d6:ef 5785 -47 [WPA-PSK-CCMP+TKIP][WPA2-PSK-CCMP+TKIP][WPS][ESS] Fibertel WiFi114 5.8GHz");
int wap_scan_size = wap_scan_count_lines(scan);
scan_result = malloc(wap_scan_size * sizeof(**scan_result));
int i = 0;
int item_len = sizeof (*scan_result);
while((line = strsep(&scan, "\n")) != NULL ) {
if(i==0){
i++;
continue;
}
char **scan_line = calloc(5, item_len);
int j = 0;
while ((item = strsep(&line, "\t")) != NULL) {
printf("%s\n", item);
scan_line[j++] = strdup(item);
}
scan_result[i++] = scan_line;
}
return 0;
}真正的功能给了我这个问题:
char *** wifi_client_get_wap_list(int *len)
{
char ***scan_result;
char *buf, *buf_free, *cmd, *line, *item;
int ret, items_len;
cmd = strdup("SCAN");
ret = wpa_ctrl_command(cmd, NULL);
if (ret < 0) goto error;
cmd = strdup("SCAN_RESULTS");
ret = wpa_ctrl_command(cmd, &buf); //RETURNS A STRING ON BUF ALLOCATED BY STRDUP
if (ret < 0){
free(buf);
goto error;
}
*len = wap_scan_count_lines(buf); //NUMBER OF LINES IN THE SCAN RESULT
scan_result = calloc(*len, sizeof(**scan_result));
int i = 0, j;
buf_free = buf;
items_len = sizeof (*scan_result);
while ((line = strsep(&buf, "\n"))){ //THIS GIVES THE SEGFAULT AT THE END
// SKIP FIRST LINE WITH HEADERS
if (i==0){
i++;
continue;
}
//if (strcmp(line, "") == 0) {
// break;
//}
//EACH LINE HAS 5 VALUES (bssid, freq, level,flags,ssid)
char **scan_line = calloc(5, items_len);
j = 0;
printf("INNER STEPS:\n");
while((item = strsep(&line, "\t"))){
*(scan_line + j) = strdup(item);
printf("%d ", j);
j++;
}
*(scan_result + i) = scan_line;
printf("\nSTEP: %d\n", i);
i++;
}
free(buf_free);
free(cmd);
return scan_result;
error:
// @TODO: Handle error
if (ret == -2) {
printf("'%s' command timed out.\n", cmd);
} else if (ret < 0) {
printf("'%s' command failed.\n", cmd);
}
free(cmd);
return NULL;
}发布于 2021-03-11 00:37:28
基于https://man7.org/linux/man-pages/man3/strsep.3.html,问题是循环将比您希望的多运行一次,从而导致scan_result溢出。
文件的有关部分如下:
The strsep() function returns a pointer to the token, that is, it
returns the original value of *stringp.和
If *stringp is NULL, the strsep() function returns NULL and does
nothing else. Otherwise, this function finds the first token in
the string *stringp, that is delimited by one of the bytes in the
string delim. This token is terminated by overwriting the
delimiter with a null byte ('\0'), and *stringp is updated to
point past the token. In case no delimiter was found, the token
is taken to be the entire string *stringp, and *stringp is made
NULL.在wap_scan_count_lines中,计算以'\n‘结尾的行数。
在下面的2行中,根据以'\n‘结尾的行数分配内存以保存结果。
int wap_scan_size = wap_scan_count_lines(scan);
scan_result = malloc(wap_scan_size * sizeof(**scan_result));但是,上述引用的 strsep ()文档意味着,在您的简化示例中,调用第一个乘以strsep,在调用结束时,结果将不是NULL,而扫描在调用期间不会设置为NULL。下一次通过调用,扫描将在调用期间设置为NULL,但结果不会为NULL。这意味着循环的主体将执行wap_scan_size +1次,从而导致scan_result.结束后的写入。
至少有两个可能的修复,取决于您是否真的想要处理输入末尾没有被'\n‘终止的任何行。
如果您确实需要处理这些行,这对我来说似乎更健壮,特别是考虑到简化的示例以这样的行结尾,那么只需在scan_result中分配一个额外的条目即可。
scan_result = malloc((wap_scan_size + 1) * sizeof(**scan_result));如果您确信不需要处理这些行,但这在我看来是不正确的,请更改:
while((line = strsep(&scan, "\n")) != NULL ) {至
for(line = strsep(&scan, "\n"); scan != NULL; line = strsep(&scan, "\n") ) {https://stackoverflow.com/questions/66567040
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