在下面的Hive-query中,我需要映射父标记下的子标记,其值与XML内容的值相同。到目前为止,交叉连接正在发生,因为父标记值"ABCD“在这里重复。
with your_data as (
select '<ParentArray>
<ParentFieldArray>
<Name>ABCD</Name>
<Value>
<string>111</string>
<string></string>
</Value>
</ParentFieldArray>
<ParentFieldArray>
<Name>ABCD</Name>
<Value>
<string/>
<string>444</string>
<string>555</string>
</Value>
</ParentFieldArray>
</ParentArray>' as xmlinfo
)
select name, case when value='NULL' then '' else value end value
from (select regexp_replace(xmlinfo,'<string></string>|<string/>','<string>NULL</string>') xmlinfo
from your_data d
) d
lateral view outer explode(XPATH(xmlinfo, 'ParentArray/ParentFieldArray/Name/text()')) pf as Name
lateral view outer explode(XPATH(xmlinfo, concat('ParentArray/ParentFieldArray[Name="', pf.Name, '"]/Value/string/text()'))) vl as value;查询的预期输出:
Name Value
ABCD 111
ABCD
ABCD
ABCD 444
ABCD 555发布于 2021-03-11 12:25:46
除了名称之外,您还可以使用position ()代替instead ()来获得位置。然后在第二个XPATH中按位置筛选数组,在本例中可能不需要名称筛选器,在更大的数据集中调试它。我使用了两种方法:名称和索引过滤器,它适用于您的数据示例。XPATH中的位置从1开始,在单元格中的位置从0开始,这就是使用pos+1的原因:
with your_data as (
select '<ParentArray>
<ParentFieldArray>
<Name>ABCD</Name>
<Value>
<string>111</string>
<string></string>
</Value>
</ParentFieldArray>
<ParentFieldArray>
<Name>ABCD</Name>
<Value>
<string/>
<string>444</string>
<string>555</string>
</Value>
</ParentFieldArray>
</ParentArray>' as xmlinfo
)
select name, pos+1 as pos, case when value='NULL' then '' else value end value
from (select regexp_replace(xmlinfo,'<string></string>|<string/>','<string>NULL</string>') xmlinfo
from your_data d
) d
lateral view outer posexplode(XPATH(xmlinfo, 'ParentArray/ParentFieldArray/Name/text()')) pf as pos, Name
lateral view outer explode(XPATH(xmlinfo, concat('((ParentArray/ParentFieldArray)[',pf.pos+1, '])[Name="', pf.Name, '"]/Value/string/text()'))) vl as value;结果:
name pos value
ABCD 1 111
ABCD 1
ABCD 2
ABCD 2 444
ABCD 2 555https://stackoverflow.com/questions/66580649
复制相似问题