在python中将图从字典形式转化为矩阵

Question

{‘X 050412_1_0000_4’：{'0-4'：64.9516586968339，'2-3'：47.573389284767174，'1-2'：29.414889381739993，'0-1'：20.137499912849165，'0-2'：48.36841808990657，'0-3'：65.07665932728878，'1-3'：58.326301639483376，'3-4'：42.477331382632784，'1-4'：47.380533137671634，'2-4'：18.99533464493748}，‘X 050412_1_0000_1_5：{'0-4'：74.45548880223673，'2-3'：42.921786085506746，'1-2'：22.297921437434468，'0-1'：16.755486281812296，'0-2'：31.640265835324445，'0-3'：49.53140665618129，'1-3'：55.29908155494086，'3-4'：25.4227462686469，'1-4'：78.22578893907047，'2-4'：61.73419510554909}，‘X 050412_1_0000_1_6：{'0-4'：53.36246109354403，'2-3'：49.125438624810265，'1-2'：26.33647295558006，'0-1'：27.165619713343553，'0-2'：53.21604990987211，'0-3'：31.972624680029007，'1-3'：34.38869991232585，'3-4'：35.1262268074706，'1-4'：33.29462873873201，'2-4'：23.60048014617499}假设我有一个像这样表示的图，我想要创建它来将它转换成矩阵形式。

Answer 1

for k,v in dataset.distances.items():
if k not in diz2:
    diz2[k] = {}
for k2,v2 in v.items():
    res = tuple(map(int, k2.split('-')))
    if res not in diz2:
        diz2[k][res] = v2

def convert(diz5):
temp_x = max([cord[0] for cord in diz5.keys()])
temp_y = max([cord[1] for cord in diz5.keys()])
res2 = [[0] * (temp_y + 1) for ele in range(temp_x + 1)]
for (i, j), val in diz5.items():
    res2[i][j] = val
#print("The dictionary after creation of Matrix : " + str(res2))
return  res2