在FLAUI中,尝试获取以某些字母开头或包含一些字母的子元素的引用。示例以或" doc“或包含"DOC”开始,我要做的是打开一些办公室文件,如doc、xls、ppt。并希望在他打开屏幕时附加该文件。
foreach (var file in listOfFiles)
{
if (file.Name.Contains("DOC") || file.Name.Contains("PPT") || file.Name.Contains("XLS") || file.Name.Contains("TXT"))
{
file.AsButton().Invoke();
var window = new UIA3Automation();
desktopWindow = window.GetDesktop();
desktopWindow = WaitForElement(() => desktopWindow.FindFirstChild(cr => cr.ByName("// Here want to put name that start with ... or contains ...")));
var app = FlaUI.Core.Application.Attach(desktopWindow.Properties.ProcessId);
var application = app.GetMainWindow(new UIA3Automation());
CloseingProcess(application.Name);发布于 2021-12-13 20:50:49
如果我正确理解了您的意思,您需要检查已经打开的文件是否具有所需的扩展名。对,是这样?
为此,您必须使用FlaUI获取窗口,然后检查Window类上的属性.Title,如下所示:
var automation = new UIA3Automation();
var app = FlaUI.Core.Application.Attach(application.Process.Id); //attach or start application here
var window = app.GetMainWindow(automation); //Get hold
window.Title //Use the .Title or .TitleBar property to check for your extension.https://stackoverflow.com/questions/66709871
复制相似问题