.subset2中的错误(x，i，精确=精确)：递归索引在第2级失败

Question

我正在尝试重新计算我的教育变量，从一个18级的因素到一个7级的因素，从没有资格的GCSE D，GCSE A*-C- A级-Undergraduate -Postgraduate -其他。

bes[[bes$education]]%>% recode('No qualification' = 'no qualification',
                               'GCSE D-G, CSE grades 2-5, O level D-E' = 'GCSE D-G',
                               'Youth training certificate, skill seekers' = 'GCSE D-G',
                               'Clerical and commercial qualifications'= 'GCSE D-G',
                               'GCSE A*-C, CSE grade 1, O level grade A-C'  = 'GCSE A*-C',
                               'Scottish Standard grades, Ordinary bands' = 'GCSE A*-C',
                               'Recognised trade apprenticeship' = 'GCSE A*-C',
                               'City&Guilds level 1, NVQ/SVQ 1 and equivalent' = 'GCSE A*-C',
                                 'A level or equivalent '= 'A level',
                               'Scottish Higher or equivalent'= 'A level',
                               'City&Guilds level 2, NVQ/SVQ 2 and equivalent'= 'A level',
                               'HNC/HND, City&Guilds level 4, NVQ/SVQ 4/5'= 'A level',
                               'ONC/OND, City&Guilds level 3, NVQ/SVQ 3'= 'A level',
                               'Univ/poly diploma'= 'Undergraduate',
                               'First degree'= 'Undergraduate',
                               'Nursing qualification'= 'Undergraduate',
                               'Teaching qualification'= 'Undergraduate',
                               'Postgraduate degree'  = 'Postgrad',
                               'Other technical, professional or higher qualification' = "Other")

我在这样做的时候遇到了困难，我不断地收到错误信息。我尝试过使用ifelse函数和各种其他函数，这些函数都来自基r、dplyr和plyr包，但我似乎仍然做不到。

Answer 1

第一个命令的语法是错误的。使用bes[[bes$education]]代替bes$education。方括号[[]]与列数和$符号及其名称一起使用。它要么是[[]]，要么是$，但两者都不是。