如何使用“if is”表达式来生成一个逐字拼凑的句子，从而生成整个句子

Question

我正在编写一些代码，其中我想(逐字逐句地)将以下句子的变体拼凑在一起，但我正在处理我的“if”和“else if”的用法

You are in a twisting little maze of passages, all different.

事实上，我总共有12句话要说：

        You are in a twisting little maze of passages, all different.
        You are in a little twisting maze of passages, all different.
        You are in a twisty little maze of passages, all different.
        You are in a little twisty maze of passages, all different.
        You are in a little maze of twisting passages, all different.
        You are in a little maze of twisty passages, all different.
        You are in a twisting maze of little passages, all different.
        You are in a twisty maze of little passages, all different.
        You are in a maze of twisting little passages, all different.
        You are in a maze of little twisting passages, all different.
        You are in a maze of twisty little passages, all different.
        You are in a maze of little twisty passages, all different.

我使用的变量如下：

1) int little  /  2) int twist  /  3) int twisting   / 4) int before

它们的职能如下：

1. 在以上句子中首先考虑的性质是形容词“小”是放在名词“迷宫”之前，还是在名词“段落”之前。换句话说，什么是小的，迷宫还是段落？这面旗帜将被称为“小”。这是函数的第一个参数。如果“小”的值是0，那么“小”就出现在“迷宫”之前，就像上面的前六句话一样。如果“小”的值是1，那么“小”就在“段落”之前，就像上面的最后六句话一样。--

1. 第二个属性类似于第一个属性。这个性质是指扭形形容词(“扭”或“扭”)是出现在名词“迷宫”之前还是在名词“段落”之前。这面旗帜将被称为“扭曲”。这是函数的第二个论点。如果“扭曲”的值为0，那么扭转形容词就会出现在“迷宫”之前。如果“扭曲”的值是1，那么扭转形容词就在“段落”之前。--

1. 第三个属性是扭形形容词是“扭”还是“扭”。这面旗帜将被称为“扭曲”。这是函数的第三个论点。如果“扭”的值是0，那么扭转形容词就是“扭”。如果“扭”的值是1，那么扭形形容词就是“扭”。--

1. 第四个性质是形容词“小”是出现在扭形形容词之前还是后面，如果两个形容词都修改了同一个名词。这面旗帜将被称为“前面”。这是函数的第四个论点。如果“前面”的值为0，那么“小”则出现在“扭”形容词之后。如果“前面”的值是1，那么“小”就会出现在扭形形容词之前。当两个形容词不在同一个名词前面时，这个标志没有任何区别，这就是为什么只有12个不同的句子。

我有以下思路：

#include <stdio.h>

void mazesentence(int little, int twist, int twisting, int before)
{
    
    printf("You are in a ");
    
    
    if(little == 0 && twist == 0)
    {
        if(before == 0)
        {
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1);
                printf("twisting ");
            printf("little ");
        }
        else if(before == 1)
            printf("little ");
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1);
                printf("twisting ");
        printf("of maze ");
    }
           
    
    if(little == 1 && twist == 1)
    {
        if(before == 0)
        {
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1);
                printf("twisting ");
            printf("little");
        }
        else if(before == 1)
            printf("little ");
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1);
                printf("twisting ");
        printf("passages");
    }
        
    printf("passages, all different.\n");

    return;
}

int main( )
{
    mazesentence(0, 0, 1, 0);
    mazesentence(0, 0, 1, 1);
    mazesentence(0, 0, 0, 0);
    mazesentence(0, 0, 0, 1);
    mazesentence(0, 1, 1, 0);
    mazesentence(0, 1, 0, 0);
    mazesentence(1, 0, 1, 0);
    mazesentence(1, 0, 0, 0);
    mazesentence(1, 1, 1, 0);
    mazesentence(1, 1, 1, 1);
    mazesentence(1, 1, 0, 0);
    mazesentence(1, 1, 0, 1);

    return 0;
}

但是，输出如下：

You are in a twisting little twisting of maze passages, all different.
You are in a little twisting of maze passages, all different.
You are in a twisty twisting little twisty twisting of maze passages, all different.
You are in a little twisty twisting of maze passages, all different.
You are in a passages, all different.
You are in a passages, all different.
You are in a passages, all different.
You are in a passages, all different.
You are in a twisting littletwisting passagespassages, all different.
You are in a little twisting passagespassages, all different.
You are in a twisty twisting littletwisty twisting passagespassages, all different.
You are in a little twisty twisting passagespassages, all different.

这12句话需要与上述12句话相匹配。除了额外的“扭曲”，第一句几乎是一样的。我做错了什么？

Answer 1

代码中有一些错误，逻辑中也有其他错误：

1. 'else if‘由于';’没有做任何事情，它之后的printf每次都会出现。

否则如果(扭曲== 1)；打印(“扭曲")；

这是正确的使用方法：

否则，如果(扭转== 1) printf(“扭曲");

1. 在逻辑上也有一些问题，所以会有时间它什么也不做。--

我稍微修改了一下您的代码，它正在工作：

void mazesentence(int little, int twist, int twisting, int before)
{

printf("You are in a ");


if(twist == 0)
{
    if(before == 0){
        if (twisting == 0){
            printf("twisty ");
        } else if (twisting == 1){
            printf("twisting ");
        }
        if(little == 0){
            printf("little ");  
        }
    }else if(before == 1){
        if(little == 0){
            printf("little ");  
        }
        if(twisting == 0)
            printf("twisty ");
        else if(twisting == 1)
            printf("twisting ");
    }
    printf("maze of ");
    if(little == 1){
        printf("little ");
    }
}else if(twist == 1){
    
    if(little == 0){
        printf("little maze of ");
        if(before == 1){
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1)
                printf("twisting ");
        }
    }else if(little == 1){
        printf("maze of ");
        if(before == 1){
            printf("little ");  
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1)
                printf("twisting ");
        }else if(before == 0){
            if(twisting == 0)
                printf("twisty ");
            else if(twisting == 1)
                printf("twisting ");
            printf("little ");  
        }
    }
}
    
printf("passages, all different.\n");

return;
}

int main( )
{
    mazesentence(0, 0, 1, 0);
    mazesentence(0, 0, 1, 1);
    mazesentence(0, 0, 0, 0);
    mazesentence(0, 0, 0, 1);
    mazesentence(0, 1, 1, 1);
    mazesentence(0, 1, 0, 1);
    mazesentence(1, 0, 1, 0);
    mazesentence(1, 0, 0, 0);
    mazesentence(1, 1, 1, 0);
    mazesentence(1, 1, 1, 1);
    mazesentence(1, 1, 0, 0);
    mazesentence(1, 1, 0, 1);

    return 0;
}