我有一个定制的gradle任务,只在作为参数传递的文件上运行detekt。
tasks.register("detektCustom", io.gitlab.arturbosch.detekt.Detekt.class) { detektTask ->
detektTask.config.from("$rootDir/app/config/detekt/detekt.yml")
detektTask.jvmTarget = "1.8"
detektTask.classpath.setFrom(project.configurations.getByName("detekt"))
detektTask.reports {
txt {
enabled = true
destination = file("${project.buildDir}/reports/detekt/detekt.txt")
}
xml {
enabled = true
destination = file("${project.buildDir}/reports/detekt/detekt.xml")
}
html {
enabled = false
destination = file("${project.buildDir}/reports/detekt/detekt.html")
}
}
if (project.hasProperty("kotlinFiles")) {
def kotlinFiles = project.property("kotlinFiles")
def listOfFiles = kotlinFiles.split(",")
detektTask.source = files(listOfFiles)
}
}但是使用类型解析的自定义detekt规则在这个gradle任务中不能正常工作。
我已经读过,传递适当的classpath和jvmTarget应该有效。我是不是在上面的分级任务中遗漏了什么?
发布于 2021-06-23 14:41:47
更新:
我找到了办法。将其添加到detekt任务配置中。
对于android模块:
def baseExtension = project.extensions.findByType(com.android.build.gradle.BaseExtension.class)
def bootClasspath = project.files(baseExtension.bootClasspath)
baseExtension.applicationVariants.all { variant ->
if (variant.name.contains("buildFlavorNameHere")) {
classpath.setFrom(variant.getCompileClasspath(null).filter { it.exists() } + bootClasspath)
}
}图书馆模块:
def baseExtension = project.extensions.findByType(com.android.build.gradle.BaseExtension.class)
def bootClasspath = project.files(baseExtension.bootClasspath)
baseExtension.libraryVariants.all { variant ->
if (variant.name.contains("buildFlavorNameHere")) {
classpath.setFrom(variant.getCompileClasspath(null).filter { it.exists() } + bootClasspath)
}
}唯一的区别是baseExtension.applicationVariants和baseExtension. libraryVariants
https://stackoverflow.com/questions/66958595
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