我试图用邻接列表和PQ作为Min堆来实现单目标最短路径的Dijkstra算法。输出必须显示所有顶点到目标顶点的路径,如果存在路径,如果存在路径,则显示其之和(最短),如果没有,则不显示路径。链接到整个代码
输入格式:
4
1 2 4 3 5 4 5
4 1 7 3 3
2 1 3 4 10 据GDB分析,发现extractMin函数存在分割故障。
Program received signal SIGSEGV, Segmentation fault.
0x00401746 in extractMin ()Client.c
从text.txt文件中提取输入并创建有向图
FILE *fptr = fopen("test.txt", "r");
if (fptr == NULL) exit(1);
int n;
if (fscanf(fptr, "%d", &n) == 1 && n > 0)
{
Graph *graph = createGraph(n);
int c;
while ((c = fgetc(fptr)) != EOF && c != '\n');
char *line = NULL;
size_t len = 0;
while (getline(&line, &len, fptr) > 0)
{
char *cur = line;
int ccs = 0;
int v1;
if (sscanf(cur, "%d%n", &v1, &ccs) == 1)
{
cur += ccs;
int v2;
int w;
while (sscanf(cur, "%d %d%n", &v2, &w, &ccs) == 2)
{
addEdge(graph, v1, v2, w);
cur += ccs;
}
fputc('\n', stdout);
}
}
free(line);
for (int i = 0; i < n; i++)
dijkstra(graph, i);
}Server.c
struct MinHeapNode* extractMin(MinHeap* minHeap)
{
if (isEmpty(minHeap))
return NULL;
struct MinHeapNode* root = minHeap->array[0];
struct MinHeapNode* lastNode = minHeap->array[minHeap->size - 1];
minHeap->array[0] = lastNode;
minHeap->pos[root->v] = minHeap->size-1;
minHeap->pos[lastNode->v] = 0;
--minHeap->size;
minHeapify(minHeap, 0);
return root;
}
void dijkstra(Graph* graph, int dest)
{
int v = graph->vertices;
int distance[v];
int pathFollow[1000]={0};
int ind = 0;
MinHeap* minHeap = createMinHeap(v);
for (int i = 0; i < v; ++i)
{
distance[v] = INT_MAX;
minHeap->array[v] = newMinHeapNode(v, distance[v]);
minHeap->pos[v] = v;
}
minHeap->array[dest] = newMinHeapNode(dest, distance[dest]);
minHeap->pos[dest] = dest;
distance[dest] = 0;
decreaseKey(minHeap, dest, distance[dest]);
minHeap->size = v;
while (!isEmpty(minHeap))
{
struct MinHeapNode* minHeapNode = extractMin(minHeap);
int u = minHeapNode->v;
AdjListNode* path = graph->array[u].head;
while (path != NULL)
{
int v = path->vertex;
if (isInMinHeap(minHeap, v) && distance[u] != INT_MAX &&
path->weight + distance[u] < distance[v])
{
distance[v] = distance[u] + path->weight;
if(pathFollow[ind-1] != u)
pathFollow[ind++]=u;
decreaseKey(minHeap, v, distance[v]);
}
path = path->next;
}
}
printArr(distance, v, pathFollow, dest);
}
void printArr(int dist[], int n, int pathFollow[], int dest)
{
printf("%d", dest+1);
int j = 0;
if(dist[n-1]!=0 && dist[n-1] < 100000000)
{
int k = j;
printf(" %d", pathFollow[k]+1);
while(pathFollow[j]!=0)
{
printf(" %d", pathFollow[j++]);
}
printf(" %d %d\n",n, dist[n-1]);
}
else
{
printf("NO PATH\n");
}
}发布于 2021-04-15 21:20:36
我不打算调试整个程序,但是这里有几个错误:
然后访问graph->array[src].head。
这是一个问题,因为n只是顶点的总数,在您的示例4中,但是当使用类似于4 1 7的东西调用该addEdge()时,即堆缓冲区溢出。您需要说明您创建的0-indexed数组。
但这就是我们所说的
distance[v] = INT_MAX;同样,不考虑0-indexed数组。此外,该代码似乎可疑,应该是distance[i] = INT_MAX,我相信。
请检查您自己的代码以获得更多这样的错误,特别是对于数组索引溢出,使用地址消毒液检查内存错误的代码,遍历程序的每一行,看看是否确实发生了什么。您提到了extractMin()周围的程序错误。检查它是否正在访问它应该访问的内存。SIGSEGV表示非法内存访问。struct MinHeapNode* root是否指向您分配的东西?struct MinHeapNode* lastNode是否指向您分配的东西?
https://stackoverflow.com/questions/67108205
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