C++：我在find()上遇到了麻烦

Question

我对c++不是很有经验，而且我在编写一个学习字符串函数的程序时遇到了麻烦。我试过通过编写其他程序来单独测试这些功能来排除故障。

预期行为:它在“”之前确定一个名称，在后面确定一个整数。

演示行为:返回w/a空白名称和0。

我的平台是linux/x86。

//I included my essential libraries and declared
//used functions.

#include <iostream>
using std::cout;
using std::cin;

#include <string>
using std::string;

int main()
{
    
    //Made the string and initialized it w/filler text.
    
    string uni="patchy 0000";
    cout << "Name the leprechaun and\ngive how much gold they have\n(seperate w/space please) \n";
    
    //I printed some text on the prompt
    //[addmitedly with bad formatting,]
    //and appended the input from the cin
    //function into "uni".

    cin >> uni;
    
    //Here I tried to find the name by
    //making a substring of everything
    //before the first " " in "uni", with
    //the numbers after being the value
    //of "gold".

    string nam=uni.substr(0,uni.find(" "-1));
    int gold=uni.find(" "+1);
 
    //Here's where the values are printed to
    //the console.

    cout << "Their name is " << nam << '!' << '\n';
    cout << "And, they have " << gold << " gold!" << '\n';
    return 0;
}

Answer 1

尝试使用getline(cin，uni)。cin本身只读到第一个空格。此外，find()函数返回您搜索的字符串的位置。您可能也希望对gold使用substr()函数。

编辑:我相信您的意思是在find()函数括号外写'+1‘和'-1’，以获得空格前后的位置。这也可能导致错误。