试图在分隔符之间匹配字符

Question

分隔符是-(在破折号前后有空格)，文本是：Information and Telecommunication - Salaries and Wages - Non-Management。我试图匹配的文本是Information and Telecommunication、Salaries and Wages和Non-Management

我得到的最接近的正则表达式是(\s-\s)?[\w\s]+(\s-\s)?，但不幸的是，匹配产生了Non和Management作为单独的匹配。

另一个要尝试的案例：Information and Telecommunication - Salaries and Wages - Non-Management - 1--2

Answer 1

您可以将空格与可选连字符-匹配，也可以将连字符与可选空格-匹配，但不匹配-。

\w+(?:(?: -*|-+ ?)\w+)*

模式匹配

• \w+匹配1+字字符
• (?:非捕获群
  • (?: -*|-+ ?)匹配和0+ -或匹配1+倍-和可选
  • \w+匹配1+字字符

• )*关闭非捕获组并可选择重复

Regex演示

Answer 2

实际上，您需要的是匹配单词字符的正则表达式，或者在-或行尾之前的空格或连字符。

下面的正则表达式应该执行

(\w(?:[\w\s]|\w-\w)*)(?=(?:\s-\s)|$)

解释

(             # matching group start
  \w          # match any word character once
    (?:       # start of a non-matching group
      [\w\s]  # match any word character or space character
      |       # OR
      \w-\w   # match any hyphen that's in between two word characters
    )*        # find this non-matching group zero or multiple times
)             # matching group end
(?=           # lookahead start
  (?:\s-\s)   # non-matching group for space hyphen space
  |           # OR
  $           # end of string
)             # lookahead end

演示