我有一个PHP表单供用户编辑个人详细信息。由于某些原因,我需要知道哪个值已经被用户修改了,而不是覆盖数据库中的所有细节。加载页面后,首先执行on语句,从数据库中获取内容并显示在页面上。单击表单的submit按钮后,if语句将被执行。
<?php
$everywhere = [];
if($_SERVER['REQUEST_METHOD'] == 'POST'){
//once the submit button is clicked, collect all the values from the form
$edited = [];
$edited['Name']= ...;
$edited['Address'] = ...;
//error
//$everywhere becomes undefined
global $everywhere;
foreach($everywhere as $x=>$x_val){
echo "<h2>".$x."=".$x_val." "."</h2>";
}
}else{
//sqli_ query line
//sqli_fetch_assoc line
//original personal details will be stored into $items
$items = [];
$items['Name'] = ...;
$items['Address'] = ...;
global $everywhere;
$everywhere = $items;
}
?>
<!--display original personal details-->
<form method="post">
<dl>
<dt>Name</dt>
<dd><input type="text" name="user_name" value="<?php echo $items['user_name']; ?>"/></dd>
</dl>
......
......
<input type="submit" value="Edit"/>
</form>我计划比较if语句中的$everywhere和$edited,以便知道哪个值已被修改。但是$everywhere在if语句中变得没有定义。有什么办法解决这个问题吗?
发布于 2021-04-24 02:30:28
if语句中有$everywhere的拼写错误,而else语句中有另一个拼写错误。
...
global $everywhere;
foreach(**$everywhere** as $x=>$x_val){
echo "<h2>".$x."=".$x_val." "."</h2>";
}
...
global **$everywhere**;
$everywhere = $items;
}
?>
...https://stackoverflow.com/questions/67238785
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