我正在尝试做一个bmi计算器,但我得到了一个NameError问题,即使我已经定义了bmi计算器。我的代码是这样的:
name1 = 'Person1'
height1_m = 1.7
weight1_kg = 54
name2 = 'Person2'
height2_m = 2
weight2_kg = 70
name3 = 'Person3'
height3_m = 1
weight3_kg = 1000
def bmi_calculator(name, height_m, weight_kg):
bmi = weight_kg / (height_m ** 2)
print(name + "'s bmi is: " + bmi)
if bmi > 25
print(name + 'is overweight')
else
print(name + 'is not overweight')
result1 = bmi_calculator(name1, height1_m, weight1_kg)
result2 = bmi_calculator(name2, height2_m, weight2_kg)
result3 = bmi_calculator(name3, height3_m, weight3_kg)
NameError Traceback (most recent call last)
<ipython-input-10-31aab3e09e71> in <module>
----> 1 result1 = bmi_calculator(name1, height1_m, weight1_kg)
2 result2 = bmi_calculator(name2, height2_m, weight2_kg)
3 result3 = bmi_calculator(name3, height3_m, weight3_kg)
NameError: name 'bmi_calculator' is not defined发布于 2021-05-09 08:10:29
第一个问题是,如果需要和 of ,则冒号()位于的末尾。
第二个问题是,您试图隐式地将float转换为str。
这样做是可行的:
name1 = 'Person1'
height1_m = 1.7
weight1_kg = 54
name2 = 'Person2'
height2_m = 2
weight2_kg = 70
name3 = 'Person3'
height3_m = 1
weight3_kg = 1000
def bmi_calculator(name, height_m, weight_kg):
bmi = weight_kg / (height_m ** 2)
print(str(name) + "'s bmi is: " + str(bmi))
if bmi > 25:
print(name + 'is overweight')
else:
print(name + 'is not overweight')
result1 = bmi_calculator(name1, height1_m, weight1_kg)
result2 = bmi_calculator(name2, height2_m, weight2_kg)
result3 = bmi_calculator(name3, height3_m, weight3_kg)https://stackoverflow.com/questions/67455500
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