如何从一张牌中获得最高牌的正确获胜者

Question

我从python开始，我正在尝试编写一个纸牌游戏，用户和计算机在其中玩5轮。用户和计算机必须从我创建的那张牌中得到一张随机的卡片，而获胜者是最高的一张牌。

我的代码中有几个问题。

例如，当我创建整个扑克牌时，我得到了"bastos“卡的输出：

"8 de bastos“、"9 de bastos”、"10 de bastos“和"11 de bastos”而不是"sota de bastos“、"caballo de bastos”、"rey de bastos“和"as de bastos”。

这种情况只发生在"bastos“中，因为它是列表中的第一个变量。但我不知道怎么解决这个问题。

然后，我也有一个问题的结果：

Tu carta es caballo de oros > Your card is King of Gold
La carta del ordenador es sota de espadas > Your card is Jokey of Spades 
Esta ronda la ha ganado el ordenador. > The computer has won this round. 

所以我的节目说电脑在不正常的时候赢了。

我在绘图方面也有类似的问题。我的课程不认可任何抽签，例如：

Tu carta es 5 de espadas > Your card is 5 of spaces
La carta del ordenador es 5 de copas > Computer's card is 5 of coups. 
Has ganado. > You have won. 

到目前为止，这就是我的全部代码：

import random

print("Who will be the best out of 5 rounds?")

contador_humano = 0
contador_ordenador = 0
rondas = 0

while rondas < 5:
    rondas = rondas + 1
    print("\nRounds", rondas)

    palos = ["bastos", "copas", "espadas", "oros"]
    num = [2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
    baraja = []
    for n in num:
        for palo in palos:
            carta = "{} de {}".format(n,palo)
            for c in carta:
                if n == 8:
                    n = sota
                elif n == 9:
                    n = "caballo"
                elif n == 10:
                    n = "rey"
                elif n == 11:
                    n = "as"
            baraja.append(carta)
    random.shuffle(baraja)
    input("\nPress enter to shuffle.")
    print(baraja)

    carta_humano = random.choice(baraja)
    print("\nThis is your card", carta_humano)
    baraja.remove(carta_humano)
    carta_ordenador = random.choice(baraja)
    print("This is the computer card", carta_ordenador)
    
    if carta_humano > carta_ordenador:
        contador_humano += 1
        contador_ordenador += 0
        print("\nYou have won this round.")
    elif carta_humano == carta_ordenador:
        contador_humano += 0
        contador_ordenador += 0
        print("\nThis is a draw.")
    else:
        contador_humano += 0
        contador_ordenador += 1
        print("\nThe computer has won this round.")

    baraja.append(carta_humano)
    random.shuffle(baraja)

print("\nFinal score:", contador_humano, " - ", contador_ordenador)
            
if contador_humano > contador_ordenador:
    print("You win!")
elif contador_humano == contador_ordenador:
    print("It is a draw.")
elif contador_humano < contador_ordenador:
    print("You lose.")

Answer 1

人类知道什么检查，看看'7杯card =‘card 2’> oros‘>是否意味着纸牌游戏.然而，计算机不理解卡片，它只知道你告诉它每一张卡都是一个字符串，它根据字符串的内容对表达式进行评估以确定谁赢了。

要解决比较每张卡的整个字符串"{n} de {palo}“的问题，您需要只获取每张卡的num部分(我假设这就是我们正在检查的部分，如果我错了，请更正)，您可以将字符串拆分成单词(其中一个单词是字符串中由空格分隔的部分)，并将字符串中的第一个单词(因为我们知道这是数字)放入一个变量中，然后使用这个变量来确定谁赢了。

我拿出了你把8-11转换成sota的代码块，就像现在一样。我将在这里编辑，当我使它工作时，如何修复它。现在，这里是您的代码减去这个块，我添加了两行代码并编辑了另外两行代码，现在它给出了预期的赢家。

import random

print("Who will be the best out of 5 rounds?")

contador_humano = 0
contador_ordenador = 0
rondas = 0

while rondas < 5:
    rondas = rondas + 1
    print("\nRounds", rondas)

    palos = ["bastos", "copas", "espadas", "oros"]
    num = [2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
    baraja = []
    for n in num:
        for palo in palos:
            carta = "{} de {}".format(n,palo)
            baraja.append(carta)
    random.shuffle(baraja)
    input("\nPress enter to shuffle.")
    print(baraja)
    
    carta_humano = random.choice(baraja)
    print("\nThis is your card", carta_humano)
    baraja.remove(carta_humano)
    carta_ordenador = random.choice(baraja)
    print("This is the computer card", carta_ordenador)

    # get the number portion of carta_humano
    num_carta_humano = int(carta_humano.split()[0])
    
    # get the number portion of carta_ordenador
    num_carta_ordenador = int(carta_ordenador.split()[0])
        
    if num_carta_humano > num_carta_ordenador: # compare numeric portion of each card
        contador_humano += 1
        contador_ordenador += 0
        print("\nYou have won this round.")
    elif num_carta_humano == num_carta_ordenador: # compare numeric portion of each card
        contador_humano += 0
        contador_ordenador += 0
        print("\nThis is a draw.")
    else:
        contador_humano += 0
        contador_ordenador += 1
        print("\nThe computer has won this round.")

    baraja.append(carta_humano)
    random.shuffle(baraja)

print("\nFinal score:", contador_humano, " - ", contador_ordenador)
            
if contador_humano > contador_ordenador:
    print("You win!")
elif contador_humano == contador_ordenador:
    print("It is a draw.")
elif contador_humano < contador_ordenador:
    print("You lose.")

编辑：

您的另一半问题是，您的代码用sota替换8-11，这并不像预期的那样起作用。

我修正了您的代码，使其按照您的意愿运行。由于您需要用sota替换8-11的唯一原因--就像打印卡片时一样，我更改了代码，这样卡片本身就不会改变，但是打印出来的是。我在导入的顶部添加了一个函数。当你打印纸牌和卡片时，这个功能被用来用sota-as代替8-11，但是它不会改变原来的牌，只是打印的东西。

以下是包含所有更改的完整更正代码：

import random

def replace_num_carta(baraja, carta):
    # return the text representation of a card, replacing 8-11 with sota-as

    if int(carta.split()[0]) == 8: # if the first word in the split string is 8
        return ('sota de ' + carta.split()[-1]) # print 'sota de' concatenated to the last word of the split string
    elif int(carta.split()[0]) == 9: # if the first word in the split string is 9
        return ('caballo de ' + carta.split()[-1]) # print 'caballo de' concatenated to the last word of the split string
    elif int(carta.split()[0]) == 10: # if the first word in the split string is 10
        return ('rey de ' + carta.split()[-1]) # print 'rey de' concatenated to the last word of the split string
    elif int(carta.split()[0]) == 11: # if the first word in the split string is 11
        return ('as de ' + carta.split()[-1]) # print 'as de' concatenated to the last word of the split string
    else:
        return(carta)

print("Who will be the best out of 5 rounds?")

contador_humano = 0
contador_ordenador = 0
rondas = 0

while rondas < 5:
    rondas = rondas + 1
    print("\nRounds", rondas)

    palos = ["bastos", "copas", "espadas", "oros"]
    num = [2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
    baraja = []
    for n in num:
        for palo in palos:
            carta = "{} de {}".format(n,palo)
            baraja.append(carta)
    random.shuffle(baraja)
    input("\nPress enter to shuffle.")

    baraja_to_print = []
    for carta in baraja:
        baraja_to_print.append(replace_num_carta(baraja, carta)) # append the current card, after running through the function replace_num_carta

    print(baraja_to_print)

    carta_humano = random.choice(baraja)
    print("\nThis is your card " + replace_num_carta(baraja, carta_humano))
    baraja.remove(carta_humano)
    carta_ordenador = random.choice(baraja)
    print("This is the computer card " + replace_num_carta(baraja, carta_ordenador))

    # get the number portion of carta_humano
    num_carta_humano = int(carta_humano.split()[0])
    
    # get the number portion of carta_ordenador
    num_carta_ordenador = int(carta_ordenador.split()[0])
        
    if num_carta_humano > num_carta_ordenador: # compare numeric portion of each card
        contador_humano += 1
        contador_ordenador += 0
        print("\nYou have won this round.")
    elif num_carta_humano == num_carta_ordenador: # compare numeric portion of each card
        contador_humano += 0
        contador_ordenador += 0
        print("\nThis is a draw.")
    else:
        contador_humano += 0
        contador_ordenador += 1
        print("\nThe computer has won this round.")

    baraja.append(carta_humano)
    random.shuffle(baraja)

print("\nFinal score:", contador_humano, " - ", contador_ordenador)
            
if contador_humano > contador_ordenador:
    print("You win!")
elif contador_humano == contador_ordenador:
    print("It is a draw.")
elif contador_humano < contador_ordenador:
    print("You lose.")

Answer 2

一些问题：

• for c in carta将迭代carta的每个字符。这不是在您将值赋值给intended.
• Changing carta.
• When n之后所做的，不会更改carta.
• When比较carta_humano > carta_ordenador，您正在比较这些字符串，因此，例如，"rey“将被视为大于"as”。您需要比较cards.
• "sotas“的数值必须引用

我建议为一个卡片创建一个类，这个类就像一个带有秩和适合属性的元组，它有一个__repr__方法，负责生成“尼斯”名称。通过将其定义为元组，顺序基于第一个成员(排名)，这正是我们所需要的。

我也不会随便乱选一张牌。如果你已经洗牌了，你可以只拿最后一张牌。这和随机选择一样是随机的。你把选定的牌放回甲板上，但在我看来，这是过火了。有足够的牌打5轮，所以不要费心地把他们放回去。但这只是我的观点。这对你的问题并不重要。

最后的elif可以只是一个else，因为只剩下一种可能性了。

以下是它的工作原理：

import random
from collections import namedtuple

class Card(namedtuple('Card', ['rank', 'suit'])):
    def __repr__(self):
        return "{} of {}".format(self.rank if self.rank < 8 else ["sota", "caballo", "rey", "as"][self.rank-8], self.suit)

print("Who will be the best out of 5 rounds?")

contador_humano = 0
contador_ordenador = 0

baraja = [Card(rank, suit) 
                for suit in ["bastos", "copas", "espadas", "oros"]
                for rank in [2, 3, 4, 5, 6, 7, 8, 9, 10, 11]]
random.shuffle(baraja)
for rondas in range(1, 6):
    input("\nPress enter to start round {}".format(rondas))
    carta_humano = baraja.pop()
    print("\nThis is your card: {}".format(carta_humano))
    carta_ordenador = baraja.pop()
    print("This is the computer card: {}".format(carta_ordenador))
    
    if carta_humano > carta_ordenador:
        contador_humano += 1
        print("\nYou have won this round.")
    elif carta_humano == carta_ordenador:
        print("\nThis is a draw.")
    else:
        contador_ordenador += 1
        print("\nThe computer has won this round.")

print("\nFinal score:", contador_humano, " - ", contador_ordenador)
            
if contador_humano > contador_ordenador:
    print("You win!")
elif contador_humano == contador_ordenador:
    print("It is a draw.")
else:
    print("You lose.")