如何创建一个while循环，直到5个变量都等于10

Question

import random

damage_1 = random.randint(1, 10)
damage_2 = random.randint(1, 10)
damage_3 = random.randint(1, 10)
damage_4 = random.randint(1, 10)
damage_5 = random.randint(1, 10)

entries = 0

while damage_1 != 10 and damage_2 != 10 and damage_3 != 10 and damage_4 != 10 and damage_5 != 10:
  entries = entries + 1
  print(entries)
  print(damage_1)
  print(damage_2)
  print(damage_3)
  print(damage_4)
  print(damage_5)

while循环应该一直添加到条目 var，直到所有damage_X vars等于10为止。

Answer 1

您应该首先将所有变量初始化为0，然后在while循环中随机生成它们。

import random
damage_1 = damage_2 = damage_3 = damage_4 = damage_5 = 0
entries = 0
while damage_1 != 10 and damage_2 != 10 and damage_3 != 10 and damage_4 != 10 and damage_5 != 10:
    entries = entries + 1
    print(entries)
    damage_1 = random.randint(1, 10)
    damage_2 = random.randint(1, 10)
    damage_3 = random.randint(1, 10)
    damage_4 = random.randint(1, 10)
    damage_5 = random.randint(1, 10)
    print(damage_1)
    print(damage_2)
    print(damage_3)
    print(damage_4)
    print(damage_5)

应该是这样的。但你没有提到你被困在哪里。

Answer 2

因此，为了实现您想要的，继续循环并将1添加到条目中，直到所有damage_X变量都等于10为止。

import random
damage_1 = damage_2 = damage_3 = damage_4 = damage_5 = 0
entries = 0
while damage_1 != 10 or damage_2 != 10 or damage_3 != 10 or damage_4 != 10 or damage_5 != 10:
    entries += 1
    print(entries)
    if damage_1 != 10: damage_1 = random.randint(1, 10)
    if damage_2 != 10: damage_2 = random.randint(1, 10)
    if damage_3 != 10: damage_3 = random.randint(1, 10)
    if damage_4 != 10: damage_4 = random.randint(1, 10)
    if damage_5 != 10: damage_5 = random.randint(1, 10)
    print(damage_1)
    print(damage_2)
    print(damage_3)
    print(damage_4)
    print(damage_5)
    print("")

因此，您应该检查damage_X是否等于10，并且只有当它没有为其分配新的随机整数时才进行检查。如果不添加“如果检查”，则循环将运行很长时间，因为所有5个damage_X变量同时等于10的可能性极低。我在of语句中将和更改为或，如果使用和，如果_XE 226变量的one =E 12710<代码>E 228，则循环将停止。