将字符串数组按另一个字符串数组排序的最有效方法是什么？

Question

我的问题

如何通过Javascript中的另一个字符串数组对字符串数组进行排序？

背景

我正在寻找通过另一个数组排序字符串数组的方法。具体来说，我有一个问题，我不能按字母或数字排序。我知道Javascript支持自定义排序函数，如本例所示：

let numberArray = [40, 1, 5, 200];
function compareNumbers(a, b) {
  return a - b;
}
numberArray.sort(compareNumbers);

我不确定自定义字符串比较函数将如何工作，以解决我正在研究的问题。我在下面第1部分和第2部分中给出了两个示例数组。如果您需要进一步的澄清，请询问。

第1部分

示例数组：注意到educationSorted是按educationLevel排序education的理想结果。

let education = [
  "High School",
  "Middle School",
  "Undergrad",
  "Middle School",
  "Middle School",
  "Middle School",
  "Middle School",
  "Graduate",
  "Elementary",
  "Elementary",
  "Elementary",
  "Elementary"
];

let educationLevel = ["Elementary", "Middle School", "High School", "Undergrad", "Graduate"];

let educationSorted = [
  "Elementary",
  "Elementary",
  "Elementary",
  "Elementary",
  "Middle School",
  "Middle School",
  "Middle School",
  "Middle School",
  "Middle School",
  "High School",
  "Undergrad",
  "Graduate"
];

第2部分

相同的一般问题，但字符串数组被数组替换。

let education = [
  ["Bob", "High School"],
  ["Alice", "Middle School"],
  ["Jane Doe", "Undergrad"],
  ["alex", "Middle School"],
  ["Mega Alice", "Middle School"],
  ["Jhon Doe", "Middle School"],
  ["Minor Bob", "Middle School"],
  ["Chicken", "Graduate"],
  ["Minor Chicken", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"]
];

let educationLevel = ["Elementary", "Middle School", "High School", "Undergrad", "Graduate"];

let education = [
  ["Clones", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"],
  ["Minor Chicken", "Elementary"],
  ["Alice", "Middle School"],
  ["Mega Alice", "Middle School"],
  ["Jhon Doe", "Middle School"],
  ["Minor Bob", "Middle School"],
  ["alex", "Middle School"],
  ["Bob", "High School"],
  ["Jane Doe", "Undergrad"],
  ["Chicken", "Graduate"]
];

Answer 1

用这个：

​

let education = [
  ["Bob", "High School"],
  ["Alice", "Middle School"],
  ["Jane Doe", "Undergrad"],
  ["alex", "Middle School"],
  ["Mega Alice", "Middle School"],
  ["Jhon Doe", "Middle School"],
  ["Minor Bob", "Middle School"],
  ["Chicken", "Graduate"],
  ["Minor Chicken", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"]
];

let educationLevel = ["Elementary", "Middle School", "High School", "Undergrad", "Graduate"];

function sortFunc(a, b) {
  return educationLevel.indexOf(a[1]) - educationLevel.indexOf(b[1]);
}

education.sort(sortFunc);
console.log(education);

​

Answer 2

您可以尝试使用这样的自定义排序函数：

const educationLevel = [
  "Elementary",
  "Middle School",
  "High School",
  "Undergrad",
  "Graduate",
];

const education = [
  ["Bob", "High School"],
  ["Alice", "Middle School"],
  ["Jane Doe", "Undergrad"],
  ["alex", "Middle School"],
  ["Mega Alice", "Middle School"],
  ["Jhon Doe", "Middle School"],
  ["Minor Bob", "Middle School"],
  ["Chicken", "Graduate"],
  ["Minor Chicken", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"],
  ["Clones", "Elementary"],
];

const compareEntries = (a, b) => {
  const aPriority = educationLevel.findIndex((element) => {
    return element === a[1];
  });
  const bPriority = educationLevel.findIndex((element) => {
    return element === b[1];
  });
  return aPriority - bPriority;
};

education.sort(compareEntries);

此方法使用educationLevel数组的索引来确定排序顺序。