如何用start_index和end_index查找句子中单词的位置

Question

示例1 :

start = 42
end = 48
string = "This is in line with others, showing that Noggin can function as a BMP-6 antagonist [21,22]."

Output = [9,9]

使用开始索引和结束索引，如何返回完整单词的索引？(在开始位置和结尾位置，这是字符串的第九个单词)

示例2 :

start = 42
end = 52
string = "This is in line with others, showing that Noggin can function as a BMP-6 antagonist [21,22]."

Output = [9,10]

在第二种情况下，选择了多个单词，因此我们需要返回第一个单词的索引(Noggin)和最后一个单词的索引(can)。

示例3(输出总是2个数字) :

start = 42
end = 61
string = "This is in line with others, showing that Noggin can function as a BMP-6 antagonist [21,22]."

Output = [9,11]

Output = first_word_index，last_word_index

示例4(如果在末尾选择了一个空格，我们不关心) :

start = 42
end = 49
string = "This is in line with others, showing that Noggin can function as a BMP-6 antagonist [21,22]."

Output = [9,9]

示例5(如果没有完全选择单词) :

start = 42
end = 51
string = "This is in line with others, showing that Noggin can function as a BMP-6 antagonist [21,22]."

Output = [9,10]

如果一个词没有被完全选中，我们的表现就像它被完全选中了一样。

​

​

Answer 1

以下功能应适用于任何示例：

def words(start,end,string):
    c=1    
    l=[]
    for i in range(end):
        if string[i]==' ':
            c=c+1
        if i==start:
            l.append(c)
    if string[i]!=' ':
        l.append(c)
    else:
        l.append(c-1)
    return l

Answer 2

可以使用正则表达式，查找所有单词，这将返回索引的一个元组：

from typing import Tuple

def word_index(string : str, start : int, end : int) -> Tuple[int, int]:
    import re

    word_re = re.compile(r'\w+')

    start_index = len(word_re.findall(string[:start+1]))
    end_index = len(word_re.findall(string[:end]))

    return start_index, end_index

word_index(42, 48) # (9, 9)
word_index(42, 52) # (9, 10)
word_index(42, 61) # (9, 11)
word_index(42, 49) # (9, 9)
word_index(42, 51) # (9, 10)