尝试使用XSLT动态组合/分组行项(标头、行、收费),在一个“记录”下具有相同的"invoice_id“值。
在输入XML中,有多个条目,如标头、行、电荷,它们的出现是无界的。
在输出XML中,我们试图在一个父节点"Record“下对其发票id相等的标题、行和费用进行分组。父节点"Record“重复的次数与输入XML中的发票id相同。
请在下面找到投入和预期产出:
输入XML输入XML如下:
<?xml version="1.0" encoding="utf-8"?>
<ns:MT_OkayToPay_Source xmlns:ns="http://kpmg.com/xi/Coupa/OkayToPay">
<Header>
<type>Header</type>
<invoice_id>5</invoice_id>
</Header>
<Header>
<type>Header</type>
<invoice_id>6</invoice_id>
</Header>
<Line>
<type>Line</type>
<invoice_id>5</invoice_id>
</Line>
<Line>
<type>Line</type>
<invoice_id>6</invoice_id>
</Line>
<Charge>
<type>Charge</type>
<invoice_id>5</invoice_id>
<invoice_charge_invoice_id>10</invoice_charge_invoice_id>
</Charge>
<Charge>
<type>Charge</type>
<invoice_id>5</invoice_id>
<invoice_charge_invoice_id>11</invoice_charge_invoice_id>
</Charge>
<Charge>
<type>Charge</type>
<invoice_id>6</invoice_id>
<invoice_charge_invoice_id>13</invoice_charge_invoice_id>
</Charge>
<Charge>
<type>Charge</type>
<invoice_id>6</invoice_id>
<invoice_charge_invoice_id>14</invoice_charge_invoice_id>
</Charge>
</ns:MT_OkayToPay_Source>输出XML输出预期如下所示
<?xml version="1.0" encoding="utf-8"?>
<ns:MT_OkayToPay_Source xmlns:ns="http://kpmg.com/xi/Coupa/OkayToPay">
<Record>
<Header>
<type>Header</type>
<invoice_id>5</invoice_id>
</Header>
<Line>
<type>Line</type>
<invoice_id>5</invoice_id>
</Line>
<Charge>
<type>Charge</type>
<invoice_id>5</invoice_id>
<invoice_charge_invoice_id>10</invoice_charge_invoice_id>
</Charge>
<Charge>
<type>Charge</type>
<invoice_id>5</invoice_id>
<invoice_charge_invoice_id>11</invoice_charge_invoice_id>
</Charge>
</Record>
<Record>
<Header>
<type>Header</type>
<invoice_id>6</invoice_id>
</Header>
<Line>
<type>Line</type>
<invoice_id>6</invoice_id>
</Line>
<Charge>
<type>Charge</type>
<invoice_id>6</invoice_id>
<invoice_charge_invoice_id>13</invoice_charge_invoice_id>
</Charge>
<Charge>
<type>Charge</type>
<invoice_id>6</invoice_id>
<invoice_charge_invoice_id>14</invoice_charge_invoice_id>
</Charge>
</Record>
</ns:MT_OkayToPay_Source>帮帮忙吧。
发布于 2021-05-29 13:03:09
找到了答案:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/*">
<root>
<xsl:for-each-group select="*" group-by="invoice_id">
<record>
<xsl:copy-of select="current-group()"/>
</record>
</xsl:for-each-group>
</root>
</xsl:template>
</xsl:stylesheet>要在XSLT1.0中实现同样的目标,请使用以下方法:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:key name="Records_by_invoice_id" match="*" use="invoice_id"/>
<xsl:template match="/*">
<MT_OkayToPay_Source>
<xsl:apply-templates/>
</MT_OkayToPay_Source>
</xsl:template>
<xsl:template match=
"MT_OkayToPay_Source/*[generate-id()=generate-id(key('Records_by_invoice_id',invoice_id)[1])]">
<record>
<xsl:copy-of select="key('Records_by_invoice_id',invoice_id)"/>
</record>
</xsl:template>
<xsl:template match=
"MT_OkayToPay_Source/*[not(generate-id()=generate-id(key('Records_by_invoice_id',invoice_id)[1]))]"/>
</xsl:stylesheet>谢谢!
问候
维沙卡·科纳
https://stackoverflow.com/questions/67743997
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