我需要在星星之火中获得前一组的值,并将其设置为当前组。我怎样才能做到这一点?我必须点菜,而不是TEXT_NUM。
由TEXT_NUM排序是不可能的,因为事件在时间上重复,如计数10和11所示。
我正在尝试使用以下代码:
val spark = SparkSession.builder()
.master("spark://spark-master:7077")
.getOrCreate()
val df = spark
.createDataFrame(
Seq[(Int, String, Int)](
(0, "", 0),
(1, "", 0),
(2, "A", 1),
(3, "A", 1),
(4, "A", 1),
(5, "B", 2),
(6, "B", 2),
(7, "B", 2),
(8, "C", 3),
(9, "C", 3),
(10, "A", 1),
(11, "A", 1)
))
.toDF("count", "TEXT", "TEXT_NUM")
val w1 = Window
.orderBy("count")
.rangeBetween(Window.unboundedPreceding, -1)
df
.withColumn("LAST_VALUE", last("TEXT_NUM").over(w1))
.orderBy("count")
.show()结果:
+-----+----+--------+----------+
|count|TEXT|TEXT_NUM|LAST_VALUE|
+-----+----+--------+----------+
| 0| | 0| null|
| 1| | 0| 0|
| 2| A| 1| 0|
| 3| A| 1| 1|
| 4| A| 1| 1|
| 5| B| 2| 1|
| 6| B| 2| 2|
| 7| B| 2| 2|
| 8| C| 3| 2|
| 9| C| 3| 3|
| 10| A| 1| 3|
| 11| A| 1| 1|
+-----+----+--------+----------+预期结果:
+-----+----+--------+----------+
|count|TEXT|TEXT_NUM|LAST_VALUE|
+-----+----+--------+----------+
| 0| | 0| null|
| 1| | 0| null|
| 2| A| 1| 0|
| 3| A| 1| 0|
| 4| A| 1| 0|
| 5| B| 2| 1|
| 6| B| 2| 1|
| 7| B| 2| 1|
| 8| C| 3| 2|
| 9| C| 3| 2|
| 10| A| 1| 3|
| 11| A| 1| 3|
+-----+----+--------+----------+发布于 2021-05-31 23:34:15
考虑使用Window函数last(columnName, ignoreNulls)在组边界上由以前的"text_num“组成的列中回填null,如下所示:
val df = Seq(
(0, "", 0), (1, "", 0),
(2, "A", 1), (3, "A", 1), (4, "A", 1),
(5, "B", 2), (6, "B", 2), (7, "B", 2),
(8, "C", 3), (9, "C", 3),
(10, "A", 1), (11, "A", 1)
).toDF("count", "text", "text_num")
import org.apache.spark.sql.expressions.Window
val w1 = Window.orderBy("count")
val w2 = w1.rowsBetween(Window.unboundedPreceding, 0)
df.
withColumn("prev_num", lag("text_num", 1).over(w1)).
withColumn("last_change", when($"text_num" =!= $"prev_num", $"prev_num")).
withColumn("last_value", last("last_change", ignoreNulls=true).over(w2)).
show
/*
+-----+----+--------+--------+-----------+----------+
|count|text|text_num|prev_num|last_change|last_value|
+-----+----+--------+--------+-----------+----------+
| 0| | 0| null| null| null|
| 1| | 0| 0| null| null|
| 2| A| 1| 0| 0| 0|
| 3| A| 1| 1| null| 0|
| 4| A| 1| 1| null| 0|
| 5| B| 2| 1| 1| 1|
| 6| B| 2| 2| null| 1|
| 7| B| 2| 2| null| 1|
| 8| C| 3| 2| 2| 2|
| 9| C| 3| 3| null| 2|
| 10| A| 1| 3| 3| 3|
| 11| A| 1| 1| null| 3|
+-----+----+--------+--------+-----------+----------+
*/中间列保存在输出中以供参考。如果不需要的话就扔掉吧。
https://stackoverflow.com/questions/67779360
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