重复的GroupBy对象数组Javascript

Question

我有一个建议：

var modbusData = [
  { Type: "rtu", Mode: "master", IdDevice: "1", Time: "11:01:00", Data: "1,12,23" },
  { Type: "tcp", Mode: "client", IdDevice: "2", Time: "11:01:11", Data: "30,40,50" },
  { Type: "rtu", Mode: "slave", IdDevice: "1", Time: "11:02:00", Data: "5,10,21" },
  { Type: "tcp", Mode: "server", IdDevice: "2", Time: "11:02:11", Data: "32,44,53" },
];

在我调用一个函数对输入进行分组之后

function groupBy(objectArray, property, expectedGroups = []) {
  return objectArray.reduce(function (acc, obj) {
    let key = obj[property]
    if (!acc[key]) {
      acc[key] = []
    }
    acc[key].push(obj)
    return acc
  }, Object.fromEntries(expectedGroups.map(k => [k, []])))
};
const groupedData = groupBy(modbusData, 'Type', [ 'rtu', 'tcp' ]);
console.log(groupedData);

其结果将是：

{
  rtu: [
    { Type: 'rtu', Mode: 'master', IdDevice: '1', Time: '11:01:00', Data: '1,12,23' },
    { Type: 'rtu', Mode: 'slave', IdDevice: '1', Time: '11:02:00', Data: '5,10,21' }
  ],
  tcp: [
    { Type: 'tcp', Mode: 'client', IdDevice: '2', Time: '11:01:11', Data: '30,40,50' },
    { Type: 'tcp', Mode: 'server', IdDevice: '2', Time: '11:02:11', Data: '32,44,53' }
  ]
}

现在我想要一个带有模式的重复GroupBy，特别是当任何模式都不存在时，它们将返回空数组，结果是：

{
  rtu: {
    master: [{ Type: 'rtu', Mode: 'master', IdDevice: '1', Time: '11:01:00', Data: '1,12,23' }],
    slave: [{ Type: 'rtu', Mode: 'slave', IdDevice: '1', Time: '11:02:00', Data: '5,10,21' }]
  },
  tcp: {
    client: [{ Type: 'tcp', Mode: 'client', IdDevice: '2', Time: '11:01:11', Data: '30,40,50' }],
    server: [{ Type: 'tcp', Mode: 'server', IdDevice: '2', Time: '11:02:11', Data: '32,44,53' }]
  }
}

Edit1: SubRequest:输入时：

var modbusData = [
  { Type: "rtu", Mode: "master", IdDevice: "1", Time: "11:01:00", Data: "1,12,23" },
  { Type: "tcp", Mode: "client", IdDevice: "2", Time: "11:01:11", Data: "30,40,50" },
];

我希望输出在空数组中还包含模式从和服务器，如下所示：

{
  rtu: {
    master: [{ Type: 'rtu', Mode: 'master', IdDevice: '1', Time: '11:01:00', Data: '1,12,23' }],
    slave: []
  },
  tcp: {
    client: [{ Type: 'tcp', Mode: 'client', IdDevice: '2', Time: '11:01:11', Data: '30,40,50' }],
    server: []
  }
}

Answer 1

您可以在最后再添加一个步骤，重用您的groupBy方法，并使用Object.entries和Object.fromEntries。

const subGroupedData = Object.fromEntries(Object.entries(groupedData)
    .map( ([key,values]) => ([key, groupBy(values,'Mode')])))

活生生的例子：

​

var modbusData = [
  { Type: "rtu", Mode: "master", IdDevice: "1", Time: "11:01:00", Data: "1,12,23" },
  { Type: "tcp", Mode: "client", IdDevice: "2", Time: "11:01:11", Data: "30,40,50" },
  //{ Type: "rtu", Mode: "slave", IdDevice: "1", Time: "11:02:00", Data: "5,10,21" },
  //{ Type: "tcp", Mode: "server", IdDevice: "2", Time: "11:02:11", Data: "32,44,53" },
];

function groupBy(objectArray, property, expectedGroups = []) {
  return objectArray.reduce(function (acc, obj) {
    let key = obj[property]
    if (!acc[key]) {
      acc[key] = []
    }
    acc[key].push(obj)
    return acc
  }, Object.fromEntries(expectedGroups.map(k => [k, []])))
};
const groupedData = groupBy(modbusData, 'Type', [ 'rtu', 'tcp' ]);

const expectedSubGroups = {rtu: ['master','slave'], tcp:['client','server']}

const subGroupedData = Object.fromEntries(Object.entries(groupedData)
        .map( ([key,values]) => ([key, groupBy(values,'Mode', expectedSubGroups[key])])))

console.log(subGroupedData);

​