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社区首页 >问答首页 >检查Flux.jl模型中参数的总数?

检查Flux.jl模型中参数的总数?
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Stack Overflow用户
提问于 2021-06-27 13:47:23
回答 1查看 474关注 0票数 1

我知道,使用Flux.jl,我可以通过julia> Flux.params(model)来获取参数,但是输出并没有告诉我模型本身实际存在多少个总参数。是否有一个函数来检查这个,或者用一个编程的方法来计算这个?

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回答 1

Stack Overflow用户

回答已采纳

发布于 2021-07-12 00:54:00

正如@mcabbott在注释中提到的那样,您可以将整个模型传递给params函数,以获得每个层的总计数(sum(length, params(model)))或循环,如下所示:

代码语言:javascript
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julia> model = Chain(
         resnet[1:end-2],
         Dense(2048, 1000),  
         Dense(1000, 256),
         Dense(256, 2),        # we get 2048 features out, and we have 2 classes
       )
Chain(Chain(Conv((7, 7), 3=>64), MaxPool((3, 3), pad=1, stride=2), Metalhead.ResidualBlock((Conv((1, 1), 64=>64), Conv((3, 3), 64=>64), Conv((1, 1), 64=>256)), (BatchNorm(64), BatchNorm(64), BatchNorm(256)), Chain(Conv((1, 1), 64=>256), BatchNorm(256))), Metalhead.ResidualBlock((Conv((1, 1), 256=>64), Conv((3, 3), 64=>64), Conv((1, 1), 64=>256)), (BatchNorm(64), BatchNorm(64), BatchNorm(256)), identity), Metalhead.ResidualBlock((Conv((1, 1), 256=>64), Conv((3, 3), 64=>64), Conv((1, 1), 64=>256)), (BatchNorm(64), BatchNorm(64), BatchNorm(256)), identity), Metalhead.ResidualBlock((Conv((1, 1), 256=>128), Conv((3, 3), 128=>128), Conv((1, 1), 128=>512)), (BatchNorm(128), BatchNorm(128), BatchNorm(512)), Chain(Conv((1, 1), 256=>512), BatchNorm(512))), Metalhead.ResidualBlock((Conv((1, 1), 512=>128), Conv((3, 3), 128=>128), Conv((1, 1), 128=>512)), (BatchNorm(128), BatchNorm(128), BatchNorm(512)), identity), Metalhead.ResidualBlock((Conv((1, 1), 512=>128), Conv((3, 3), 128=>128), Conv((1, 1), 128=>512)), (BatchNorm(128), BatchNorm(128), BatchNorm(512)), identity), Metalhead.ResidualBlock((Conv((1, 1), 512=>128), Conv((3, 3), 128=>128), Conv((1, 1), 128=>512)), (BatchNorm(128), BatchNorm(128), BatchNorm(512)), identity), Metalhead.ResidualBlock((Conv((1, 1), 512=>256), Conv((3, 3), 256=>256), Conv((1, 1), 256=>1024)), (BatchNorm(256), BatchNorm(256), BatchNorm(1024)), Chain(Conv((1, 1), 512=>1024), BatchNorm(1024))), Metalhead.ResidualBlock((Conv((1, 1), 1024=>256), Conv((3, 3), 256=>256), Conv((1, 1), 256=>1024)), (BatchNorm(256), BatchNorm(256), BatchNorm(1024)), identity), Metalhead.ResidualBlock((Conv((1, 1), 1024=>256), Conv((3, 3), 256=>256), Conv((1, 1), 256=>1024)), (BatchNorm(256), BatchNorm(256), BatchNorm(1024)), identity), Metalhead.ResidualBlock((Conv((1, 1), 1024=>256), Conv((3, 3), 256=>256), Conv((1, 1), 256=>1024)), (BatchNorm(256), BatchNorm(256), BatchNorm(1024)), identity), Metalhead.ResidualBlock((Conv((1, 1), 1024=>256), Conv((3, 3), 256=>256), Conv((1, 1), 256=>1024)), (BatchNorm(256), BatchNorm(256), BatchNorm(1024)), identity), Metalhead.ResidualBlock((Conv((1, 1), 1024=>256), Conv((3, 3), 256=>256), Conv((1, 1), 256=>1024)), (BatchNorm(256), BatchNorm(256), BatchNorm(1024)), identity), Metalhead.ResidualBlock((Conv((1, 1), 1024=>512), Conv((3, 3), 512=>512), Conv((1, 1), 512=>2048)), (BatchNorm(512), BatchNorm(512), BatchNorm(2048)), Chain(Conv((1, 1), 1024=>2048), BatchNorm(2048))), Metalhead.ResidualBlock((Conv((1, 1), 2048=>512), Conv((3, 3), 512=>512), Conv((1, 1), 512=>2048)), (BatchNorm(512), BatchNorm(512), BatchNorm(2048)), identity), Metalhead.ResidualBlock((Conv((1, 1), 2048=>512), Conv((3, 3), 512=>512), Conv((1, 1), 512=>2048)), (BatchNorm(512), BatchNorm(512), BatchNorm(2048)), identity), MeanPool((7, 7)), #103), Dense(2048, 1000), Dense(1000, 256), Dense(256, 2))

julia> paramCount = 0
0

julia> for layer in model
           paramCount += sum(length, params(layer))
       end

julia> paramCount
25840234

在本例中,我只是在递增计数,但您可以将每个层的计数附加到数组中,例如,以单独跟踪每个层的计数。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/68151834

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