6510/6502 C64键盘输入打印到屏幕并存储内存问题

Question

通过查看我的c64参考书中的屏幕显示部分，我在下面输入的字符正在正确地打印屏幕，但是当回忆以后再次从内存中打印出来时，它们就不是了。:(

基本上，如果输入一个"A“，我得到黑桃符号，"S”作为心脏符号回来，"X“作为一个俱乐部回来。我必须声明这种情况不会发生，因为我输入的用户，并看到我的文本打印到屏幕-这是很好的工作。只有当我按回车时才会出错，因为我认为用户和字符存储在$1000，x( inx发生在按下键后)在分配区域的更低处显示为符号，后面是@符号，以构成我所能看到的其余字节中的空空间。

不好意思，杂乱无章的/新设计的代码，我已经学习了一个星期左右-只有基本的作为一个排序的基础。

我运行调试器，当在程序中输入"ASX“时，通过调试器的内存位置看起来如下.

41 53 58 00 00 00♠♥♣@

;USER INPUTS NAME OF CORPORATION

getnamea
        ldx #00
        ldy #00
        jmp getnameb

getnameb
       ; ldx $0900   ; transfer the x value here to a safe address

        jsr $FF9F   ;SCNKEY, place ASCII character into keyboard queue
        jsr $FFE4   ;GETIN, this places the ASCII value into the Accumulator 

        BEQ getnameb ;loop until keys are pressed. Branch if zero
        
        JSR $FFD2    ;CHROUT, print it to the screen as it is being typed in.
        CMP #13      ; CMP looks for the carrige return
        BEQ Name2    ; if we find it we branch using BEQ to name2 for msg2 
        ldx $0900
        STA $1000,x  ; also store what is being typed in consecutively? 
        INX
        INY
        stx $0900
        JMP getnameb ; if we don't we loop!        
                    
                    ; * store exactly what has been typed by the user into a place 
                    ;   in memory and give it the varible name: corpname
                    ; * display some more program defined text that includes the 
                    ; users inputted string

msg1    text 'What is the name of your corporation?'
        byte 0

;------------------------------------------------------------------------------------------------------

;PRINT MSG 2

Name2   LDX #00       ; load into the x registry zero


cycle2  LDA msg2,x    ; load into A the msg2, the x sequence.
        CMP #00       ; compare memory and accumulator to the value 0?    
        BEQ reveal   ; branch/jump if the result in A is 0
        STA 1704,x    ; where on the screen does msg2 start?
        INX           ; inc x to move the print along 1 space?
        
        JMP cycle2    ; jump back to the beginning of cycle and do it all again.

; WHAT DOES THIS DO WHEN WE JUST CALL THE ADDRESS $1000?

reveal  LDX #00
reveal1 
        LDA $1000,x
        STA 1784,x
        INX
        TXA
        CMP #16
        BEQ exit
        JMP reveal1
exit    jsr *



msg2    text `New astro mining corp registration...
        byte 0

Answer 1

问题解决了，但我想知道是否有更好的方法.

        CLC            ; clear the carry
        LDA $1000,x    ; load the character
        SBC #63        ; subtract 63 from it to get the right character in the first set