首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >带有InvokeMethodGrpcAsync() gRPC调用的Dapr gRPC SDK问题

带有InvokeMethodGrpcAsync() gRPC调用的Dapr gRPC SDK问题
EN

Stack Overflow用户
提问于 2021-07-12 15:23:55
回答 2查看 774关注 0票数 2

我有一个在Dapr中启动的应用程序,它有一个gRPC服务。用id MyGrpcApi001启动Dapr。HTTP端口: 55319。gRPC端口: 55320

我用以下命令启动了它:

dapr run --app-id MyGrpcApi001 --app-protocol grpc --app-port 5000 -- dotnet run

原语:

代码语言:javascript
复制
syntax = "proto3";

import "google/protobuf/empty.proto";

option csharp_namespace = "MyGrpcService";

package greet;

// The greeting service definition.
service Greeter {
  // Sends a greeting
  rpc SayHello (HelloRequest) returns (HelloReply);
  rpc Test (google.protobuf.Empty) returns (google.protobuf.Empty);
}

// The request message containing the user's name.
message HelloRequest {
  string name = 1;
}

// The response message containing the greetings.
message HelloReply {
  string message = 1;
}

我有一个客户端,它有两个使用gRPC连接到服务的方法

  • 一个直接通过自动生成的客户端调用服务。
  • 另一个通过dapr侧加gRPC端口
代码语言:javascript
复制
    class Program
    {
        private static string LOCAL_ADDRESS = @"http://localhost:5000";
        private static string DAPR_ADDRESS = $"http://localhost:55320";

        static async Task Main(string[] args)
        {
            await CallToLocalHost().ConfigureAwait(false); // runs OK
            await CallWithClient().ConfigureAwait(false); // exception: Service is unimplemented
        }

        private static async Task CallToLocalHost()
        {
            using var channel = GrpcChannel.ForAddress(LOCAL_ADDRESS);
            var cl = new MyGrpcService.Greeter.GreeterClient(channel);
            MyGrpcService.HelloReply response = await cl.SayHelloAsync(new MyGrpcService.HelloRequest { Name = "ThinkPad" });
            Console.WriteLine(response.Message);
        }

        private static async Task CallWithClient()
        {
            using DaprClient client = new DaprClientBuilder()
                     .UseGrpcEndpoint(DAPR_ADDRESS)
                     .Build();

            var request = new MyGrpcService.HelloRequest { Name = "ThinkPad" };
            var result = await client.InvokeMethodGrpcAsync<MyGrpcService.HelloRequest, MyGrpcService.HelloReply>("MyGrpcApi001", "SayHello", request).ConfigureAwait(false);
        }
    }

第二种方法似乎不起作用,因此直接调用起作用,但侧call似乎找不到服务。以下是这两种日志的日志:

来自正在运行的服务的日志:

第一种方法可以:

代码语言:javascript
复制
== APP == info: Microsoft.AspNetCore.Hosting.Diagnostics[1]
== APP ==       Request starting HTTP/2 POST http://localhost:5000/greet.Greeter/SayHello application/grpc -
== APP == info: Microsoft.AspNetCore.Routing.EndpointMiddleware[0]
== APP ==       Executing endpoint 'gRPC - /greet.Greeter/SayHello'
== APP == info: Microsoft.AspNetCore.Routing.EndpointMiddleware[1]
== APP ==       Executed endpoint 'gRPC - /greet.Greeter/SayHello'
== APP == info: Microsoft.AspNetCore.Hosting.Diagnostics[2]
== APP ==       Request finished HTTP/2 POST http://localhost:5000/greet.Greeter/SayHello application/grpc - - 200 - application/grpc 0.3074ms

第二个方法错误:

代码语言:javascript
复制
== APP == info: Microsoft.AspNetCore.Hosting.Diagnostics[1]
== APP ==       Request starting HTTP/2 POST http://127.0.0.1:5000/dapr.proto.runtime.v1.AppCallback/OnInvoke application/grpc -
== APP == info: Microsoft.AspNetCore.Routing.EndpointMiddleware[0]
== APP ==       Executing endpoint 'gRPC - Unimplemented service'
== APP == info: Grpc.AspNetCore.Server.Internal.ServerCallHandlerFactory[1]
== APP ==       Service 'dapr.proto.runtime.v1.AppCallback' is unimplemented.
== APP == info: Microsoft.AspNetCore.Routing.EndpointMiddleware[1]
== APP ==       Executed endpoint 'gRPC - Unimplemented service'
== APP == info: Microsoft.AspNetCore.Hosting.Diagnostics[2]
== APP ==       Request finished HTTP/2 POST http://127.0.0.1:5000/dapr.proto.runtime.v1.AppCallback/OnInvoke application/grpc - - 200 0 application/grpc 0.1474ms

第二个似乎包含了/dapr.proto.runtime. ...的错误URL。

我在这里做错什么了?dapr运行命令是错误的,还是InvokeMethodGrpcAsync方法的参数错误?

由于我可以通过自动生成的客户机直接运行该方法,所以我认为服务器正常工作,所以dapr找不到服务和/或方法。

有什么想法吗?

谢谢!

EN

回答 2

Stack Overflow用户

发布于 2022-09-14 08:36:45

我在调用gRPC服务时遇到了同样的问题。Greeter服务看起来是这样的,gRPC调用无法用问题'gRPC - Unimplemented service'来解决这个问题。

代码语言:javascript
复制
public class GreeterService : Greeter.GreeterBase
{
    public override Task<HelloReply> SayHello(HelloRequest request, ServerCallContext context)
    {
        return Task.FromResult(new HelloReply
        {
            Message = "Hello " + request.Name
        });
    }
}

相反,从AppCallbackBase类继承解决了这个问题。

代码语言:javascript
复制
public class GreeterService : AppCallback.AppCallbackBase
{
    public override async Task<InvokeResponse> OnInvoke(InvokeRequest request, ServerCallContext context)
    {
        InvokeResponse response = new();
        switch (request.Method)
        {
            case "SayHello":
                HelloRequest input = request.Data.Unpack<HelloRequest>();
                HelloReply output = await Task.FromResult(new HelloReply() { Message = "Hello " + input.Name });
                response.Data = Any.Pack(output);
                break;
            default:
                Console.WriteLine("Method not supported");
                break;
        }

        return response;
    }
}
票数 1
EN

Stack Overflow用户

发布于 2022-04-04 09:10:45

当我调用dapr端口时,我更喜欢使用Dapr代理并在grpc元数据通道中添加服务id,因为我可以直接使用Grpc方法。

您可以阅读文献资料

但是,您需要在Dapr configuration.yml文件中添加预览Dapr功能:

代码语言:javascript
复制
apiVersion: dapr.io/v1alpha1
kind: Configuration
metadata:
  name: serverconfig
spec:
  features:
    - name: proxy.grpc
      enabled: true

您可以在DaprClient.CreateInvocationInvoker SDK中检查.Net方法。

代码语言:javascript
复制
public static CallInvoker CreateInvocationInvoker(string appId, string daprEndpoint = null, string daprApiToken = null)
{
    var channel = GrpcChannel.ForAddress(daprEndpoint ?? DaprDefaults.GetDefaultGrpcEndpoint());
    return channel.Intercept(new InvocationInterceptor(appId, daprApiToken ?? DaprDefaults.GetDefaultApiToken()));
}

代码在Grpc通道中添加一个键值:"dapr- app -id":{您的app id}

示例:

代码语言:javascript
复制
var callInvoker = DaprClient.CreateInvocationInvoker("my-app-id");
var tenantServiceClient = 
    new TenantService.TenantServiceClient(callInvoker);
var tenantModel = await tenantServiceClient.FindOneAsync(new FindOneTenantRequest()
                {
                    Id = tenantId
                });
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/68349953

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档