熊猫会影响速比比赛的结果吗？

Question

我正用这个撞墙呢。Rapidfuzz提供了不同的字符串得分相似性的结果，如果我在熊猫数据框架内运行它，如果我自己运行它呢？为什么入口相似度2和最后一行的结果是不同的？

from rapidfuzz import process, utils, fuzz
import pandas as pd
import numpy as np

address_a = 'high new technology development zones huainan city anhui province china anhui anhui any city'
address_b = 'industrial park of funan city'

test_anui_data = {'Processed Client Name': ['anhui jinhan clothing co ltd'], 'Processed Aruvio Name': ['anhui jinhan clothing co ltd'], 'Processed Client Address': [address_a], 'Processed Aruvio Address': [address_b],  'Name Similarity': [89.2857142857142],  'Address Similarity': [np.nan]}  
  
# Create DataFrame  
test_anui = pd.DataFrame(test_anui_data)  
test_anui

test_anui= test_anui[(test_anui['Address Similarity'].isnull()) & (test_anui['Address Similarity']!='')]
test_anui['Address Similarity 2'] = fuzz.token_sort_ratio(str(test_anui['Processed Client Address']), str(test_anui['Processed Aruvio Address']))
print('the address similarity is different? ', fuzz.token_sort_ratio(address_a, address_b))

Answer 1

错误来自于在应用fuzz时调用整个列的事实。如果您执行以下操作，即将fuzz应用于单个行，则得到相同的结果：

test_anui= test_anui[(test_anui['Address Similarity'].isnull()) & (test_anui['Address Similarity']!='')]
test_anui['Address Similarity 2'] = fuzz.token_sort_ratio(str(test_anui.at[0,'Processed Client Address']), str(test_anui.at[0,'Processed Aruvio Address']))

print('the address similarity is different? ', fuzz.token_sort_ratio(address_a, address_b))

或者，使用.loc

test_anui= test_anui[(test_anui['Address Similarity'].isnull()) & (test_anui['Address Similarity']!='')]
test_anui['Address Similarity 2'] = fuzz.token_sort_ratio(str(test_anui.loc[0,'Processed Client Address']), str(test_anui.loc[0,'Processed Aruvio Address']))

print('the address similarity is different? ', fuzz.token_sort_ratio(address_a, address_b))

dataframe中的输出是：

    Processed Client Name         Processed Aruvio Name  \
0  anhui jinhan clothing co ltd  anhui jinhan clothing co ltd   

                            Processed Client Address  \
0  high new technology development zones huainan ...   

        Processed Aruvio Address  Name Similarity  Address Similarity  \
0  industrial park of funan city        89.285714                 NaN   

   Address Similarity 2  
0             28.099174  

fuzz.token_sort_ratio(address_a, address_b)的名字是28.099173553719012。

换句话说，您需要指定要从哪一行提取字符串。我想您的dataframe由几行组成，这意味着您必须对每一行执行以下操作：

for i in len(test_anui):
    test_anui['Address Similarity 2'] = fuzz.token_sort_ratio(str(test_anui.loc[i,'Processed Client Address']), 
    str(test_anui.loc[i,'Processed Aruvio Address']))