来自父模型'x.x‘的字段'xxx’与父模型中的'xxx‘字段冲突

Question

Django继承错误：(models.E005)

您有没有解决这个问题的解决方案，是否有方法添加前缀或idk，因为我必须有几个具有相同传统的用户？

Django不喜欢这样：

类配置f(Infos，ChefGO，ADJChefGO)：

bcs ChefGO和ADJChefGO依赖于同一个类成员，但我确实需要两个成员。

class Members(models.Model):
    phone_regex = RegexValidator(regex=r'^[0-9]{10}$', message="Error: Format 0611223344")
    indicative = models.CharField(max_length=16, default="Default indicative")
    phone = models.CharField(max_length=10, validators=[phone_regex])

    class Meta:
        abstract = True


class ChefGO(Members):
    pass


class ADJChefGO(Members):
    pass


class Dispositif(Infos, ChefGO, ADJChefGO):
    name = models.CharField(max_length=32, default="Name")
    place = models.CharField(max_length=64)
    start_date = models.DateTimeField(default=datetime.datetime.now)
    end_date = models.DateTimeField(default=datetime.datetime.now)

谢谢

Answer 1

我用这种方法找到了解决办法：

1-用“字段”和“窗体”创建“设备”类

class Device:
    @staticmethod
    class Fields:

        @staticmethod
        class Member:
            @staticmethod
            def indicative():
                return models.CharField(max_length=16, default="Default indicative")

            @staticmethod
            def phone():
                phone_regex = RegexValidator(regex=r'^[0-9]{10}$', message="Error: Format 0611223344")
                return models.CharField(max_length=10, validators=[phone_regex])

            @staticmethod
            def function():
                return models.CharField(max_length=10)

    @staticmethod
    class Forms:

        @staticmethod
        class Member:
            @staticmethod
            def indicative():
                return django.forms.TextInput(attrs={'placeholder': 'indivatif'})

            @staticmethod
            def phone(placeholder="06 12 34 56 78"):
                return django.forms.TextInput(attrs={'placeholder': placeholder})

            @staticmethod
            def function():
                return django.forms.TextInput(attrs={'placeholder': 'fonction'})

2-像这样使用“设备”字段

class ChefGO(models.Model):
    cgo_indicative = Device.Fields.Member.indicative()
    cgo_phone = Device.Fields.Member.phone()
    cgo_function = Device.Fields.Member.function()

    class Meta:
        abstract = True


class ADJChefGO(models.Model):
    adjcgo_indicative = Device.Fields.Member.indicative()
    adjcgo_phone = Device.Fields.Member.phone()
    adjcgo_function = Device.Fields.Member.function()

    class Meta:
        abstract = True

3-继承

class Dispositif(ChefGO, ADJChefGO):
    pass

4-“奖励”--你可以在ModelForm中这样使用它：

class DispositifForm(ModelForm):
    class Meta:
        model = Dispositif
        
        fields = [
                    'cgo_phone', 'cgo_indicative', 'cgo_function',
                    'adjcgo_phone', 'adjcgo_indicative', 'adjcgo_function',
                    'dso_phone', 'dso_indicative', 'dso_function'
                ]
        
        widgets = {
            'cgo_phone': Device.Forms.Member.phone(),
            'cgo_indicative': Device.Forms.Member.indicative(),
            'cgo_function': Device.Forms.Member.function(),
            
            'adjcgo_phone': Device.Forms.Member.phone(),
            'adjcgo_indicative': Device.Forms.Member.indicative(),
            'adjcgo_function': Device.Forms.Member.function(),
            
            'dso_phone': Device.Forms.Member.phone(),
            'dso_indicative': Device.Forms.Member.indicative(),
            'dso_function': Device.Forms.Member.function()
        }

Answer 2

外键能解决这个问题吗？

    # model
    class Dispositif(Infos):
        myChefGO = models.ForeignKey(ChefGO, on_delete=models.CASCADE)
        myADJChefGO = models.ForeignKey(ADJChefGO, on_delete=models.CASCADE)

    # instanciation
    dispositif = Dispositif(Infos)
    dispositif.myChefGO = A
    dispositif.myADJChefGO = B