重命名文件名，使文件以指定的排序顺序出现。

Question

我有一份文件清单。它们目前按以下顺序出现：

Advance Topics in Graphs _ Lec 11 _ Discrete Mathematics _ Exam-lAN6B0Hvy7E.webm
Basics of Combinatorics _ Lec 12 _ Discrete Mathematics _ Exam-sBg13JNUQQ8.webm
Basics of Graph Theory _ Lec 6 _ Discrete Mathematics _ Exam-JqgdPH-PEIM.webm
Basics of Relations - 2 _ Lec 20 _ Discrete Mathematics _ Exam-CTo9pvl__5M.webm
Basics of Relations _ Lec 19 _ Discrete Mathematics _ Exam-4KTaggHRd54.webm
Basics of Sets _ Lec 18 _ Discrete Mathematics _ Exam-LE-Gt_PUdws.webm

我想重命名这些文件，以便文件名具有以下模式(使用regex表示清楚)，Lec\s0-90-9出现在文件名的中间，出现在文件名的开头。(这是排序顺序)。

最终结果如下：

Lec 6 Basics of Graph Theory _  _ Discrete Mathematics _ Exam-JqgdPH-PEIM.webm
Lec 11 Advance Topics in Graphs _  _ Discrete Mathematics _ Exam-lAN6B0Hvy7E.webm
Lec 12 Basics of Combinatorics _  _ Discrete Mathematics _ Exam-sBg13JNUQQ8.webm
Lec 18 Basics of Sets _  _ Discrete Mathematics _ Exam-LE-Gt_PUdws.webm
Lec 19 Basics of Relations _  _ Discrete Mathematics _ Exam-4KTaggHRd54.webm
Lec 20 Basics of Relations - 2 _  _ Discrete Mathematics _ Exam-CTo9pvl__5M.webm

Answer 1

当我遇到这样的问题时，我倾向于用Python编写一个一次性的脚本来完成这项工作，尽管您可以用所选择的任何语言来代替它(即。( bash+awk，.)

这主要是为了确保您在真正重命名之前知道结果是什么，这可能是一个破坏性操作(抛出标识符，将所有输入文件重命名为同名，以便只有最后一个保存下来)！

import os
import re

def mapper(s):
    # adjust to taste, this just swaps the middle to the front
    prefix, index, postfix = re.match(r"^(.*) (?:Lec) (\d+) (.*)$", s).groups()
    return f"Lec {int(index):02} {prefix} {postfix}"  # pad index 2->02, etc.

mapping = {}  # start a new dictionary to store src->dest maps
for name_file in os.listdir():
    try:
        mapping[name_file] = mapper(name_file)
    except AttributeError:  # failed to match
        print(f"failed to match for {name_file}")

# display the change on separate lines
for src, dest in mapping.items():
    print(f"{src} -> {dest}")

# [return] or ^C to quit
input("continue?..")

# perform renames
for src, dest in mapping.items():
    os.rename(src, dest)

Answer 2

注意:这需要gawk，因为gensub

ls | awk '{a=gensub(/^(.*) (Lec [0-9]+) (.*)$/, "\\2 \\1\\3","1",$0);printf "mv \"%s\" \"%s\"\n",$0, a}' |  bash

Answer 3

给予：

ls -1 *.webm
Advance Topics in Graphs _ Lec 11 _ Discrete Mathematics _ Exam-lAN6B0Hvy7E.webm
Basics of Combinatorics _ Lec 12 _ Discrete Mathematics _ Exam-sBg13JNUQQ8.webm
Basics of Graph Theory _ Lec 6 _ Discrete Mathematics _ Exam-JqgdPH-PEIM.webm
Basics of Relations - 2 _ Lec 20 _ Discrete Mathematics _ Exam-CTo9pvl__5M.webm
Basics of Relations _ Lec 19 _ Discrete Mathematics _ Exam-4KTaggHRd54.webm
Basics of Sets _ Lec 18 _ Discrete Mathematics _ Exam-LE-Gt_PUdws.webm 

我只需要在Ruby中做一个小小的直线：

ruby -e 'Dir.glob("*.webm"){
        |fn| File.rename(fn, fn.sub(/^([^_]*)_ ([^_]+? )_/,"\\2\\1_ _"))}'

然后：

ls -1 *.webm
Lec 11 Advance Topics in Graphs _ _ Discrete Mathematics _ Exam-lAN6B0Hvy7E.webm
Lec 12 Basics of Combinatorics _ _ Discrete Mathematics _ Exam-sBg13JNUQQ8.webm
Lec 18 Basics of Sets _ _ Discrete Mathematics _ Exam-LE-Gt_PUdws.webm
Lec 19 Basics of Relations _ _ Discrete Mathematics _ Exam-4KTaggHRd54.webm
Lec 20 Basics of Relations - 2 _ _ Discrete Mathematics _ Exam-CTo9pvl__5M.webm
Lec 6 Basics of Graph Theory _ _ Discrete Mathematics _ Exam-JqgdPH-PEIM.webm

但是，请注意，如果新名称与以前生成的名称相同，则此(以及这里的所有其他解决方案)将覆盖一个文件.