如何在java的数组列表中存储数据列？

Question

嗨各位，我有一个Map，即字符串存储头和对象列表，分别存储它们的值。我想将数据逐个存储在数组列表中，如下所示。

这是我想要存储在数组列表中的数据格式：-

 [ Pojo(foo1=636580, foo2=CIVIL, foo3=29/06/2021),
     Pojo(foo1=636580, foo2=CIVIL, foo3=29/06/2021),
     Pojo(foo1=636580, foo2=CIVIL, foo3=29/06/2021), 
     Pojo(foo1=636580, foo2=CIVIL, foo3=29/06/2021), 
     Pojo(foo1=636580, foo2=CIVIL, foo3=29/06/2021), 
   ]

但数据存储如下：

[
     Pojo(foo1=636580, foo2=N/A, foo3=N/A),
     Pojo(foo1=636580, foo2=N/A, foo3=N/A),
     Pojo(foo1=636580, foo2=N/A, foo3=N/A), 
     Pojo(foo1=636580, foo2=N/A, foo3=N/A), 
     Pojo(foo1=636580, foo2=N/A, foo3=N/A), 
     
     Pojo(foo1=N/A, foo2=CIVIL  , foo3=N/A), 
     Pojo(foo1=N/A, foo2=CIVIL  , foo3=N/A), 
     Pojo(foo1=N/A, foo2=CIVIL  , foo3=N/A), 
     Pojo(foo1=N/A, foo2=CIVIL  , foo3=N/A), 
     Pojo(foo1=N/A, foo2=CIVIL  , foo3=N/A),


     Pojo(foo1=N/A, foo2=N/A, foo3=29/06/2021),
     Pojo(foo1=N/A, foo2=N/A, foo3=29/06/2021),
     Pojo(foo1=N/A, foo2=N/A, foo3=29/06/2021),
     Pojo(foo1=N/A, foo2=N/A, foo3=29/06/2021),
     Pojo(foo1=N/A, foo2=N/A, foo3=29/06/2021)
]

这是我的pojo课程：-

@Data
@AllArgsConstructor
@NoArgsConstructor
public class Pojo {
    private String foo1= "N/A";
    private String foo2= "N/A";
    private String foo3= "N/A";
}

这是我的密码:-

Map<String, List<Object>> myMap = new HashMap<>();
        List<String> strings = new ArrayList<>();
        strings.add("foo1");
        strings.add("foo2");
        strings.add("foo3");

        List<Pojo> pojos = new ArrayList<>();
        for (String string : strings) {
            Pojo pojo = new Pojo();
            for (Map.Entry<String, List<Object>> entry : myMap.entrySet()) {
                int max = myMap.values().stream().map(List::size).max(Integer::compareTo).get() - 1;
                if (entry.getKey().equalsIgnoreCase(string)) {
                    while (max >= 0) {
                        pojo = getPropertyValue(entry.getKey(), entry.getValue().get(max), pojo);
                        pojos.add(pojo);

                        max--;
                    }
                }
            }
        }
        System.out.println(pojos);

这是我的getPropertyValue方法:-

Class<?> unreconciledTransactionClass = Class.forName("com.example.looping.rohit.Pojo"); // convert string classname to class
        Object data;
        if (pojo != null) {
            data = pojo;
        } else {
            data = unreconciledTransactionClass.getDeclaredConstructor().newInstance(); // invoke empty constructor

        }
        PropertyAccessor myAccessor = PropertyAccessorFactory.forBeanPropertyAccess(data);
        myAccessor.setPropertyValue(attributeName, value);
        return (Pojo) data;
    }

Answer 1

下面是解决问题的代码。我添加了一个try / catch块，以便在myMap中有不同大小的列表时处理这种情况。

int max = myMap.values().stream().map(List::size).max(Integer::compareTo).get();
List<Pojo> pojos = new ArrayList<>();
for(int i=0; i<max; i++) {
    Pojo pojo = new Pojo();
    for (String string : strings) {
        String value;
        try {
             value = myMap.get(string).get(i);
        }catch(IndexOutOfBoundsException e) {
             value =  "N/A";
        }
        pojo = getPropertyValue(string,value, pojo);
    }
    pojos.add(pojo);
}