如何将javascript对象的部分存储到变量中？

Question

我对javascript很陌生，我有以下目标：

Stats: {
 "life": {
  "progress": 18,
  "counter": 1
 },
 "anxiety": {
  "progress": 24.5,
  "counter": 2
 },
 "mood": {
  "progress": null,
  "counter": 0
 },
 "cognition": {
  "progress": null,
  "counter": 0
 }
}

我需要检查焦虑、情绪和认知的计数器是否> 0，如果是的话，我必须返回True。我如何迭代这个对象并检查对象的这些特定部分？

这方面的预期产出将是

false

如果我要更新对象：

Stats: {
 "life": {
  "progress": 18,
  "counter": 1
 },
 "anxiety": {
  "progress": 24.5,
  "counter": 2
 },
 "mood": {
  "progress": null,
  "counter": 1
 },
 "cognition": {
  "progress": null,
  "counter": 1
 }
}

我想回去

True

谢谢。

Answer 1

可以将要签入数组的属性存储在数组中，使用Object.keys筛选出数组中未包含的属性，然后使用Array.every检查每个对象的counter属性是否大于0。

​

const keysToCheck = ["anxiety", "mood", "cognition"]

function validate(obj){
  return Object.keys(obj).filter(key => keysToCheck.includes(key)).every(key => obj[key].counter > 0);
}

console.log(validate({
 "life": {
  "progress": 18,
  "counter": 1
 },
 "anxiety": {
  "progress": 24.5,
  "counter": 2
 },
 "mood": {
  "progress": null,
  "counter": 0
 },
 "cognition": {
  "progress": null,
  "counter": 0
 }
}))

​

Answer 2

我希望这个代码能帮你

var obj =  {Stats: {
 "life": {
  "progress": 18,
  "counter": 1
 },
 "anxiety": {
  "progress": 24.5,
  "counter": 2
 },
 "mood": {
  "progress": null,
  "counter": 0
 },
 "cognition": {
  "progress": null,
  "counter": 0
 }
}}

Object.values(obj.Stats).every(o=> o.counter > 0)

Answer 3

使用Array.map()：

const keysToCheck = ["anxiety", "mood", "cognition"]

function validate(obj){
   let res = 0;
   keysToCheck.forEach(key =>{ if(obj[key].counter > 0) res++; })
   return res == keysToCheck.length;
}

console.log(validate({
 "life": {
  "progress": 18,
  "counter": 1
 },
 "anxiety": {
  "progress": 24.5,
  "counter": 2
 },
 "mood": {
  "progress": null,
  "counter": 0
 },
 "cognition": {
  "progress": null,
  "counter": 0
 }
}))




console.log(validate({
 "life": {
  "progress": 18,
  "counter": 1
 },
 "anxiety": {
  "progress": 24.5,
  "counter": 2
 },
 "mood": {
  "progress": null,
  "counter": 1
 },
 "cognition": {
  "progress": null,
  "counter": 1
 }
}))

​