为什么我的for循环只重复打印第一个if语句？

Question

我正试图创建一个代表棋盘的列表。我有这样的代码：

#possible list items
EMPTY = "-"
ROOK = "ROOK"
KNIGHT = "KNIGHT"
BISHOP = "BISHOP"
QUEEN = "QUEEN"
KING = "KING"
PAWN = "PAWN"
board = []

royal_row = [] #list for row containing king

pawn_row = []#list for pawn row

row = [] #generic row

#setting the board
for i in range(8):
    if i == 0 or 7:
        royal_row = [ROOK,KNIGHT,BISHOP,QUEEN,KING,BISHOP,KNIGHT,ROOK]
        board.append(royal_row)
        
    elif i == 1 or 6:
        pawn_row = [PAWN for i in range(8)]
        board.append(pawn_row)
        
    else: 
        row = [EMPTY for i in range(8)]
        board.append(row)

for i in range(8):
    print(board[i], end = "\n")

当我运行这段代码时，它只会打印：

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

我的预期产出是：

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

['PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN']

['-', '-', '-', '-', '-', '-', '-', '-']

['-', '-', '-', '-', '-', '-', '-', '-']

['-', '-', '-', '-', '-', '-', '-', '-']

['-', '-', '-', '-', '-', '-', '-', '-']

['PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN', 'PAWN']

['ROOK', 'KNIGHT', 'BISHOP', 'QUEEN', 'KING', 'BISHOP', 'KNIGHT', 'ROOK']

如果我将1、0、6和7分隔到它们自己的elif子句中，那么它将正确地打印出来，但我想了解为什么原始代码没有

Answer 1

您决定更改if's和put：i == 0 or i == 7和i == 1 or i == 6

#possible list items
EMPTY = "-"
ROOK = "ROOK"
KNIGHT = "KNIGHT"
BISHOP = "BISHOP"
QUEEN = "QUEEN"
KING = "KING"
PAWN = "PAWN"
board = []

royal_row = [] #list for row containing king

pawn_row = []#list for pawn row

row = [] #generic row

#setting the board
for i in range(8):
    if i == 0 or i == 7:
        royal_row = [ROOK,KNIGHT,BISHOP,QUEEN,KING,BISHOP,KNIGHT,ROOK]
        board.append(royal_row)

    elif i == 1 or i == 6:
        pawn_row = [PAWN for i in range(8)]
        board.append(pawn_row)

    else:
        row = [EMPTY for i in range(8)]
        board.append(row)

for i in range(8):
    print(board[i], end = "\n")

Answer 2

if i == 0 or 7:

这一声明实质上如下

if i == 0 or 7 != 0

所以，因为7总是大于1，所以它总是正确的。

若要解决此问题，请尝试以下方法

if i == 1 or i == 7