ytdl python "KeyError: formats“

Question

我试图制造一个不和谐的个人音乐机器人，因为groovy和rythm被关闭了。我想还不错，但我对ytdl有问题。输入"-play“和一个url就像预期的那样工作，但我不能输入"-play‘歌曲名称’”。输入"-play示例“将给出以下内容：

[download] Downloading playlist: example
[youtube:search] query "example": Downloading page 1
[youtube:search] playlist example: Downloading 1 videos
[download] Downloading video 1 of 1
[youtube] CLXt3yh2g0s: Downloading webpage
Ignoring exception in command play:
[download] Finished downloading playlist: example
Traceback (most recent call last):
  File "C:\Users\Dennis\PycharmProjects\groovy's true successor\venv\lib\site-packages\discord\ext\commands\core.py", line 85, in wrapped
    ret = await coro(*args, **kwargs)
  File "C:\Users\Dennis\PycharmProjects\groovy's true successor\voice.py", line 53, in play
    url2 = info['formats'][0]['url']
KeyError: 'formats'

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "C:\Users\Dennis\PycharmProjects\groovy's true successor\venv\lib\site-packages\discord\ext\commands\bot.py", line 939, in invoke
    await ctx.command.invoke(ctx)
  File "C:\Users\Dennis\PycharmProjects\groovy's true successor\venv\lib\site-packages\discord\ext\commands\core.py", line 863, in invoke
    await injected(*ctx.args, **ctx.kwargs)
  File "C:\Users\Dennis\PycharmProjects\groovy's true successor\venv\lib\site-packages\discord\ext\commands\core.py", line 94, in wrapped
    raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: KeyError: 'formats'

我对编码相当陌生，所以我很抱歉，如果有一些奇怪的事情要理解。

好的，所以:用url输入-play很好，但是输入带有歌曲名称的-play就不行了。它只搜索第一个单词，下载第一个搜索结果，然后“崩溃”。

例如，"-play Rick -永不放弃“，只搜索"Rick”，然后它说了一些关于KeyError的内容：'formats‘，这是我的代码：

@client.command()
async def play(ctx, url):
    channel = ctx.author.voice.channel
    voice = discord.utils.get(client.voice_clients, guild=ctx.guild)
    if voice and voice.is_connected():
        pass
    else:
        await channel.connect()

    ffmpeg_opts = {'before_options': '-reconnect 1 -reconnect_streamed 1 -reconnect_delay_max 5', 'options': '-vn'}
    ydl_opts = {'format': "bestaudio/best", 'default_search': 'auto'}
    vc = ctx.voice_client

    with youtube_dl.YoutubeDL(ydl_opts) as ydl:
        info = ydl.extract_info(url, download=False)
        url2 = info['formats'][0]['url']
        source = await discord.FFmpegOpusAudio.from_probe(url2, **ffmpeg_opts)
        vc.play(source)

Answer 1

#takes the entire text instead of just the first word
async def play(ctx, *,url):


#i would remove 'default_search': 'auto' and do this
ydl_opts = {'format': "bestaudio/best"}
vc = ctx.voice_client

with youtube_dl.YoutubeDL(ydl_opts) as ydl:
    url = ydl.extract_info("ytsearch:%s" % name, download = False)['entries'][0]

Answer 2

我遇到了这个问题，在做了几个小时的工作后，我发现"extract_info“在从搜索中提取而不是从url中提取时返回不同的字典。

通过使用一个简单的if检查来区分url和search，我解决了这个问题：

#check if it is a valid link
if ("youtube.com" in url or "youtu.be" in url):
#run the normal code after
    info = ydl.extract_info(url, download=False)
    url2 = info['formats'][0]['url']
    source = await discord.FFmpegOpusAudio.from_probe(url2, **FFMPEG_OPTIONS)

#if it's not a valid link but a search
else:
    info = ydl.extract_info(url, download=False)
    url2 = info['entries'][0]['webpage_url']

这个新值的"url2“在搜索部分将是对视频的链接，你应该能够把它分回与正常链接相同的东西。