我是一个新的学习者,我的问题是我如何将这些if-else语句转换为for while循环?
我试图用一种愚蠢的方法,我的逻辑如下:
1.输入号码列表
2.使用给定向量中的操作数来进行数学运算。
3.输出结果
谢谢。
int= [1, 6, 8, 4] # input int
operands=['+', '-', '*'] # input operands
sum = '+'
sub = '-'
multi = '*'
divide = '/'
z = 1
temp =0
if operands[0] == sum:
temp = int[0]+int[1]
elif operands[0] == sub:
temp =int[0] -int[1]
elif operands[0] == multi:
temp =int[0] *int[1]
elif operands[0] == divide:
temp = int[0]/int[1]
if operands[1] == sum:
temp += int[2]
elif operands[1] == sub:
temp -= int[2]
elif operands[1] == multi:
temp *= int[2]
elif operands[1] == divide:
temp /= int[2]
if operands[2] == sum:
temp += int[3]
elif operands[2] == sub:
temp -= int[3]
elif operands[2] == multi:
temp *= int[3]
elif operands[2] == divide:
temp /= int[3]
print(temp)发布于 2021-10-02 08:16:47
我想,用于循环是你所需要的
ints = [1, 6, 8, 4] # input int
operands = ['+', '-', '/'] # input operands
plus = '+'
minus = '-'
multi = '*'
divide = '/'
z = 1
temp = ints[0]
for i in range(len(operands)): # We need to get range from 0 to length of operands
if operands[i] == plus:
temp = temp + ints[i + 1]
elif operands[i] == minus:
temp = temp - ints[i + 1]
elif operands[i] == multi:
temp = temp * ints[i + 1]
elif operands[i] == divide:
temp = temp / ints[i + 1]
print(temp)还要记住,将变量命名为int或sum是个坏主意,因为它是内置的python函数。
发布于 2021-10-02 08:15:20
首先是'+‘、'-’、'*‘这些都被称为运算符..
你可以从这里得到帮助。
lst = [1, 6, 8, 4] # input int
operators =['+', '-', '*'] # input operators
sum = '+'
sub = '-'
multi = '*'
divide = '/'
z = 1
temp =0
for i in range(len(lst)-1):
if i < len(lst):
if operators[i] == sum:
temp = lst[i] + lst[i + 1]
elif operators[i] == sub:
temp = lst[i] - lst[i + 1]
elif operators[i] == multi:
temp = lst[i] * lst[i + 1]
elif operators[i] == divide:
temp = lst[i] / lst[i + 1]
print(temp)发布于 2021-10-02 08:18:32
这可能会有帮助
lst= [1, 6, 8, 4] # input int
operands=['+', '-', '*'] # input operands
temp=lst[0]
for i in range(len(lst)-1):
expr = "temp="+str(temp)+operands[i]+str(lst[i+1])
exec(expr)
print(temp)https://stackoverflow.com/questions/69415065
复制相似问题