不使用Gin的Graphql订阅

Question

当我尝试用GraphQL安装Go web服务器时，我使用了这作为模板。它基本上是杜松子酒和99designs/gqlgen的组合。

当我基于net/http包创建一个基本的gqlgen服务器时，GraphQL订阅的声明就像预期的那样工作。

package main

import (
    "log"
    "net/http"
    "os"

    "github.com/99designs/gqlgen/graphql/handler"
    "github.com/99designs/gqlgen/graphql/playground"
    "github.com/jawil003/gqlgen/graph"
    "github.com/jawil003/gqlgen/graph/generated"
)

const defaultPort = "8080"

func main() {
    port := os.Getenv("PORT")
    if port == "" {
        port = defaultPort
    }

    srv := handler.NewDefaultServer(generated.NewExecutableSchema(generated.Config{Resolvers: &graph.Resolver{}}))

    http.Handle("/", playground.Handler("GraphQL playground", "/query"))
    http.Handle("/query", srv)

    log.Printf("connect to http://localhost:%s/ for GraphQL playground", port)
    log.Fatal(http.ListenAndServe(":"+port, nil))
}

但当我加入杜松子酒时，就像这样：

package main

import (
    "github.com/gin-gonic/gin"
    "github.com/jawil003/gqlgen-todos/graph"
    "github.com/jawil003/gqlgen-todos/graph/generated"

    "github.com/99designs/gqlgen/graphql/handler"
    "github.com/99designs/gqlgen/graphql/playground"
)

// Defining the Graphql handler
func graphqlHandler() gin.HandlerFunc {
    // NewExecutableSchema and Config are in the generated.go file
    // Resolver is in the resolver.go file
    h := handler.NewDefaultServer(generated.NewExecutableSchema(generated.Config{Resolvers: &graph.Resolver{}}))

    return func(c *gin.Context) {
        h.ServeHTTP(c.Writer, c.Request)
    }
}

// Defining the Playground handler
func playgroundHandler() gin.HandlerFunc {
    h := playground.Handler("GraphQL", "/query")

    return func(c *gin.Context) {
        h.ServeHTTP(c.Writer, c.Request)
    }
}

func main() {
    // Setting up Gin
    r := gin.Default()
    r.POST("/query", graphqlHandler())
    r.GET("/", playgroundHandler())
    r.Run()
}

我明白这个问题：

{“错误”：“无法连接到websocket端点ws://localhost:8080/query。请检查端点url是否正确。”}

是否有任何已知的解决方案使gin与graphql订阅一起工作？

Answer 1

使用Gin将Could not connect to websocket endpoint..更改为r.Any("/query", graphqlHandler())修复错误r.POST("/query", graphqlHandler())

Answer 2

请把Gin和Graphql结合起来，有可能有两条不同的路线吗？一个用于查询/突变，另一个用于订阅。如下所示：

func main() {
    // Setting up Gin
    r := gin.Default()
    r.POST("/query", graphqlHandler())
    r.POST("/subscription", graphqlHandler())
    r.GET("/", playgroundHandler())
    r.Run()
}