带有Tkinker变量的Python请求

Question

如何使用tkinter中的变量执行response = requests.get()，这样我就可以发送一些bumbersto api，比如202122，并且请求看起来像"https://google.com/202122“。

def d():
  response = requests.get("myserverip/send.php?host=e2<eq>#%s#&port=e2<eq>#%s#&time=e3<eq>#%s#&method=udp") % (e1, e2, e3)
  print(response)

#call
def d1():
   threading.Thread(target=d).start()

def window():
  window = Tk()
  window.title("tools")
  window.geometry("530x240")
  Label(window, text="1").grid(row=0)
  Label(window, text="2").grid(row=1)
  Label(window, text="3").grid(row=2)
  
  e1 = Entry(window)
  e2 = Entry(window)
  e3 = Entry(window)
  
  e1.grid(row=0, column=1)
  e2.grid(row=1, column=1)
  e3.grid(row=2, column=1)

  Button(window, text='DOREQUEST', bg="gray", fg="white", command=d1).grid(row=3, column=1, sticky=E, pady=30)
       
  frame_label.place(x=210, y=0)                      

  window.mainloop()

#THREADING
p = Process(target=window)
p.start()
p.join()

Answer 1

def d():
  a = e1.get()
  b = e2.get()
  c = e3.get()
  print(a, b, c)
  request = requests.get(f"http://google.com/{a}{b}{c}".format(a, b, c))
  print(request)

#call
def d1():
   threading.Thread(target=d).start()

def window():
  window = Tk()
  window.title("tools")
  window.geometry("530x240")
  Label(window, text="1").grid(row=0)
  Label(window, text="2").grid(row=1)
  Label(window, text="3").grid(row=2)
  
  global e1, e2, e3

  e1 = Entry(window)
  e2 = Entry(window)
  e3 = Entry(window)
  
  e1.grid(row=0, column=1)
  e2.grid(row=1, column=1)
  e3.grid(row=2, column=1)

  Button(window, text='DOREQUEST', bg="gray", fg="white", command=d1).grid(row=3, column=1, sticky=E, pady=30)
       
  frame_label.place(x=210, y=0)                      

  window.mainloop()

#THREADING
p = Process(target=window)
p.start()
p.join()