按键和值筛选对象

Question

是否有条件地筛选对象，同时检查键和值？我要做的是检查键是否等于字符串，并检查值是否为空。

我想知道教学医院是否有空洞的价值，但教学医院的税务证明却没有，反之亦然。如果教学医院名称有一个值，但教学医院税务ID没有，返回的结果应该是：{教学医院税ID：""}。

对象

{
  'Manufacturer Name': 'Ascendis',
  'HCP First Name': 'John',
  'HCP Middle Name': '',
  'HCP Last Name': '',
  'HCP NPI': 2442,
  'HCP Credentials': '',
  'HCP State License Number': '',
  'HCP State of Licensure': '',
  'HCP Specialty': '',
  'Teaching Hospital Name': 'Trinity',
  'Teaching Hospital Tax ID': '',
  'Address 1': '',
  'Address 2': '',
  'Postal Code': '',
  'Spend Date': '',
  'Spend Currency': '',
  'Spend Amount': '',
  'Form of Payment': '',
  'Nature of Payment': '',
  'Home System Identifier': '',
  'Product Name': '',
  'Travel City': '',
  'Travel State': '',
  'Travel Country': ''
}

码

Object.entries(item)
          .filter(([key, value]) => (key === "Teaching Hospital Name" && value != "") && (key === "Teaching Hospital Tax ID" && value === ""))

Answer 1

让我们分析一下我们得到了什么和我们想要什么。

• 我们有一个模型obj。
• 我们希望选择特定的键，并根据选中的键/值运行特定的检查。
• 检查返回那些键值为空字符串的对象。
• 此外，如果所有值都为空，则检查将忽略结果。

我们可以把上面写成

1. if(allValues has an empty string) return false // ignore results
2. if(allValues has NOT an empty string) return false // ignore 3. results
3. return object with those keys where value is empty string

在JS中看起来就像

// your model
const obj = {}
// your group of keys you want to pick from object
const group = [];
// picked [[key,value]] defined by your group
const entries = Object.entries(obj).filter(([key]) => group.includes(key));
// filter out those which are empty
const emptyEntries = entries.filter(([key, value]) => value === ""); 
// 1. step - to check if all values are empty we can check lengths
if(entries.length === emptyEntries.length) return false;
// 2. step - just check if filtered length is 0
if(emptyEntries.length === 0) return false
// 3. step - convert your emptyEntries to object
return Object.fromEntries(emptyEntries);

让我们看看下面的代码是否适合您

​

const obj = {
  'Manufacturer Name': 'Ascendis',
  'HCP First Name': 'John',
  'HCP Middle Name': '',
  'HCP Last Name': '',
  'HCP NPI': 2442,
  'HCP Credentials': '',
  'HCP State License Number': '',
  'HCP State of Licensure': '',
  'HCP Specialty': '',
  'Teaching Hospital Name': 'Trinity',
  'Teaching Hospital Tax ID': '',
  'Address 1': '',
  'Address 2': '',
  'Postal Code': '',
  'Spend Date': '',
  'Spend Currency': '',
  'Spend Amount': '',
  'Form of Payment': '',
  'Nature of Payment': '',
  'Home System Identifier': '',
  'Product Name': '',
  'Travel City': '',
  'Travel State': 'nonempty',
  'Travel Country': ''
}
function check(obj, groupArr) {
  const group = new Set(groupArr);
  const vals = Object.entries(obj).filter(([key, value]) => group.has(key) && value === "");
  if(vals.length === group.size || vals.length === 0) return false;
  return Object.fromEntries(vals);
}
console.log(check(obj, ["Travel City", "Travel State", "Travel Country"]));
/* results
{
   "Travel City": "",
   "Travel Country": ""
}
*/

​

Answer 2

使用||而不是&&

​

const obj = {
  'Manufacturer Name': 'Ascendis',
  'HCP First Name': 'John',
  'HCP Middle Name': '',
  'HCP Last Name': '',
  'HCP NPI': 2442,
  'HCP Credentials': '',
  'HCP State License Number': '',
  'HCP State of Licensure': '',
  'HCP Specialty': '',
  'Teaching Hospital Name': 'Trinity',
  'Teaching Hospital Tax ID': '',
  'Address 1': '',
  'Address 2': '',
  'Postal Code': '',
  'Spend Date': '',
  'Spend Currency': '',
  'Spend Amount': '',
  'Form of Payment': '',
  'Nature of Payment': '',
  'Home System Identifier': '',
  'Product Name': '',
  'Travel City': '',
  'Travel State': '',
  'Travel Country': ''
}

Object.entries(obj).forEach(([key, value]) => {
    if ((key === "Teaching Hospital Name" && value != "") || (key === "Teaching Hospital Tax ID" && value === "")) {
        delete obj[key]
    }
})

console.log(obj)

​

Answer 3

您可以使用Array.prototype.reduce创建一个新对象，删除选择属性：

Object.entries(obj).reduce((acc, [key, value]) => {
  if (
    (key === "Teaching Hospital Name" && value !== "") ||
    (key === "Teaching Hospital Tax ID" && value === "")
  ) {
    // do not add key/value to resulting object
    return { ...acc };
  }

  return { ...acc, [key]: value };
}, {});

这避免了原始对象的变异。