Binance命令-> MIN_NOTIONAL x python-binance

Question

我试图为ETHUSDT创建一个OCO订单

这是我创建的函数：

def OcoOrder(symbol, bet, takeProfit, stopLoss):
    client.order_oco_sell(symbol=symbol,
                          quantity=str(bet),
                          price=str(round(takeProfit, 2)),
                          stopPrice=str(round(stopLoss, 2)),
                          stopLimitPrice =str(round(stopLoss, 2)),
                          stopLimitTimeInForce="GTC")

以下是呼叫：

buyPrice = 3803.57
stopLossValue = buyPrice * stopLoss
takeProfitValue = buyPrice * takeProfit
OcoOrder(symbol, "0.0028", takeProfitValue, stopLossValue)

我的数量是0.0028，比10 10USDT稍多一点。

​

在我执行代码后得到错误：

APIError(code=-1013): Filter failure: MIN_NOTIONAL

我检查了MIN_NOTINAL值的二进制交换信息，它是10。这意味着我可以出售的最小数量是10 ETH，换句话说，是38.000欧元？！

{
     "symbol":"ETHUSDT",
     "status":"TRADING",
     "baseAsset":"ETH",
     "baseAssetPrecision":8,
     "quoteAsset":"USDT",
     "quotePrecision":8,
     "quoteAssetPrecision":8,
     "baseCommissionPrecision":8,
     "quoteCommissionPrecision":8,
     "orderTypes":[
        "LIMIT",
        "LIMIT_MAKER",
        "MARKET",
        "STOP_LOSS_LIMIT",
        "TAKE_PROFIT_LIMIT"
     ],
     "icebergAllowed":true,
     "ocoAllowed":true,
     "quoteOrderQtyMarketAllowed":true,
     "isSpotTradingAllowed":true,
     "isMarginTradingAllowed":true,
     "filters":[
        {
           "filterType":"PRICE_FILTER",
           "minPrice":"0.01000000",
           "maxPrice":"1000000.00000000",
           "tickSize":"0.01000000"
        },
        {
           "filterType":"PERCENT_PRICE",
           "multiplierUp":"5",
           "multiplierDown":"0.2",
           "avgPriceMins":5
        },
        {
           "filterType":"LOT_SIZE",
           "minQty":"0.00010000",
           "maxQty":"9000.00000000",
           "stepSize":"0.00010000"
        },
        {
           "filterType":"MIN_NOTIONAL",
           "minNotional":"10.00000000",
           "applyToMarket":true,
           "avgPriceMins":5
        },
        {
           "filterType":"ICEBERG_PARTS",
           "limit":10
        },
        {
           "filterType":"MARKET_LOT_SIZE",
           "minQty":"0.00000000",
           "maxQty":"1459.84229583",
           "stepSize":"0.00000000"
        },
        {
           "filterType":"MAX_NUM_ORDERS",
           "maxNumOrders":200
        },
        {
           "filterType":"MAX_NUM_ALGO_ORDERS",
           "maxNumAlgoOrders":5
        }
     ],
     "permissions":[
        "SPOT",
        "MARGIN"
     ]
  },

如果我交换它，并使用USDT值作为我得到的Account has insufficient balance for requested action.的数量，因为我显然没有10个ETH

，我在监督什么吗？最小数量为10 是不可能的

Answer 1

最小符号是以美元来衡量的，而不是以硬币的数量来衡量的。这个订单一定刚刚达到了被拒绝的程度。我试过你的密码，结果成功了。然后，我缩小了.0001的增量，当我接近10美元时，我得到了最小的标记错误。

这里主要要考虑的是你的止损，它也不能低于最小值，因为你实际上是在按x值减去损失的顺序，这很可能接管了你。只是需要多做一点交易，给自己一个缓冲。

干杯朋友！