让我说我有

如您所见,0在WHO-1中有完整的响应,但也有其他类别的情况。因此,从图形上看,在geom_col-category中有三个-bars,在另外两个中有四个geom_col-bars。
如何向WHO-1中添加第四个栏,指示对应于完整响应的空间
有点像

脚本
pp %>%
as_tibble() %>%
mutate(nyWHO = as.factor(WHO),
best.resp = as.factor(case_when(best_rad == "CR" ~ 4,
best_rad == "PR" ~ 3,
best_rad == "SD" ~ 2,
best_rad == "PD" ~ 1))) %>%
count(nyWHO, best.resp) %>%
ggplot(aes(nyWHO, n, color = best.resp, fill= best.resp)) +
scale_fill_manual(values = alpha(c("#6DBCC3", "#8B3A62", "grey40", "#E1B930"), 0.4),
name="",
labels = c("Progressive disease", "Stable disease", "Partial response", "Complete response")) +
scale_colour_manual(values = cols,
name="",
labels = c("Progressive disease", "Stable disease", "Partial response", "Complete response")) +
geom_col(width=1, position = position_dodge2(width = 1, preserve = "single")) +
geom_text(aes(label = n), position = position_dodge2(width = 1, preserve = "single"),
vjust=-0.5, size = 10, show.legend = F) +
scale_x_discrete(name = "", labels = c("WHO-1", "WHO-2", "WHO-3")) +
scale_y_continuous(name="", breaks = seq(0, 80, by = 20)) +
coord_cartesian(ylim=c(0, 80)) +
theme(axis.title.x = element_text(size = 22),
axis.title.y = element_text(size = 22),
axis.text.x = ggtext::element_markdown(color = "grey20", size = 20),
axis.text.y = element_text(color = "grey20", size = 18),
panel.grid.major = element_line(colour = "gray90", size = 1.2),
panel.grid.minor = element_line(colour = "gray90", size = 0.6),
legend.text = element_text(size = 22),
legend.position = "top")数据
pp <-结构(WHO=结构(c( 3L、3L、3L、3L、3L、2L、2L、2L、2L、2L、2L、2L、2L、2L、1L、1L、3L、3L、2L、3L、1L、1L、2L、2L、1L、1L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、1L、2L、3L、2L、3L、2L、2L、1L、2L、3L、2L、2L、2L、1L、2L、3L、2L、2L、3L、3L、3L、2L、2L、1L、3L、3L、2L、2L、1L、3L、3L、2L、2L、1L、3L、3L、2L、2L、1L、1L、2L、2L、2L、2L、2L、1L、2L、3L、2L、2L、3L、2L、3L、2L、2L、1L、1L、2L、3L、2L、2L、1L、3L、3L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、2L、1L,1L,3L,2L,2L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,2L,2L,1L,1L,2L,2L,1L,1L,3L,1L,1L,3L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,2L,1L,1L,1L,3L,3L,3L,3L,2L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,2L,2L,1L,1L,3L,3L,3L,2L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,2L,1L,1L,1L,2L,2L,1L,1L,3L,1L,1L,3L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,1L,2L,1L,1L,3L,2L,2L,1L,1L,3L,1L,1L,1L,1L,1L,1L,1L,1L3L,2L,2L,2L,3L,2L,3L,3L,.Label = c("1","2","3"),类=“因子”,best_rad = c("SD","SD","CR","CR","SD","PR","CR","PR","PR","PR“、"SD”、"PD“、"PR”、"PD“、"SD”、"SD“、"PD”、"SD“、"PD”、"PR“、"PD”、"SD“、"PD”、"SD“、"SD”、"PD“、"PD”、"PD““PD”、"SD“、”PD“、"SD”、“PD”、“PD”、"SD“、"SD”、“PD”、"PD",“SD”、"PD“、”SD“、"PD”、“SD”、“SD”、"PD“、”SD“、"PD”、“SD”、"SD","SD","PD","SD","CR","SD","PD","SD","SD","SD“、"PD”、"PD“、"SD”、"SD“、"PD”、"SD“、"PD”)、row.names = c(NA、-133 L)、class = "data.frame")
发布于 2021-10-22 11:30:08
使用count(nyWHO, best.resp, .drop = FALSE)
d <- pp %>%
as_tibble() %>%
mutate(nyWHO = as.factor(WHO),
best.resp = as.factor(case_when(best_rad == "CR" ~ 4,
best_rad == "PR" ~ 3,
best_rad == "SD" ~ 2,
best_rad == "PD" ~ 1))) %>%
count(nyWHO, best.resp, .drop = FALSE)
d
# A tibble: 12 x 3
nyWHO best.resp n
<fct> <fct> <int>
1 1 1 11
2 1 2 41
3 1 3 3
4 1 4 0
5 2 1 22
6 2 2 13
7 2 3 5
8 2 4 1
9 3 1 23
10 3 2 9
11 3 3 1
12 3 4 4
ggplot(...)

发布于 2021-10-22 11:46:17
使用.drop = FALSE是解决方案,但是如果不可能的话,原始数据是不可用的,那么解决方案是通过使用联接来扩展所有级别的数据:
...
data <- pp %>%
as_tibble() %>%
mutate(nyWHO = as.factor(WHO),
best.resp = as.factor(case_when(best_rad == "CR" ~ 4,
best_rad == "PR" ~ 3,
best_rad == "SD" ~ 2,
best_rad == "PD" ~ 1))) %>%
count(nyWHO, best.resp)
data %>%
full_join(expand(data, nyWHO, best.resp), by = c("nyWHO", "best.resp")) %>%
replace_na(list(n = 0)) %>%
ggplot(aes(nyWHO, n, color = best.resp, fill= best.resp)) +
... # rest of ggplot statement

https://stackoverflow.com/questions/69675802
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