如何从内存缓冲区创建pySDL2映像

Question

我有一个pySimpleGUI程序，它从包含JPEG图像的内存缓冲区创建图像。

from PIL import ImageTk
image = ImageTk.PhotoImage( data=buf) # PhotoImage will detect a JPEG format
self.win["-IMAGE-'].update( data=image)

我想将我的应用程序转换为pySDL2。

由于pySimpleGUI和pySDL都是基于PIL的，所以我希望可以轻松地进行转换，但我无法找到从缓冲区创建SDL映像的方法。

有办法吗？

Answer 1

不确定这是可行的，未经测试，但可能会使你走上正确的轨道。如果你想要更多的细节，请访问https://rubato.app/。图像类的完整源代码就在那里。

@staticmethod
def from_surface(surface: sdl2.surface.SDL_Surface) -> "Image":
    """
    Creates an image from an SDL surface.

    Args:
        surface: the surface to create the image from.

    Returns:
        The created image.
    """
    # untested
    image = Image()
    image.image = surface
    return image

@staticmethod
def from_buffer(buffer: bytes) -> "Image":
    """
    Creates an image from a buffer.

    Args:
        buffer: bytes containing the image data.

    Returns:
        The image created from the buffer.
    """
    # untested
    rw = sdl2.SDL_RWFromMem(buffer, len(buffer))
    surface_temp = sdl2.sdlimage.IMG_Load_RW(rw, 1)

    if surface_temp is None:
        raise Exception(sdl2.sdlimage.IMG_GetError())

    surface = sdl2.SDL_ConvertSurfaceFormat(surface_temp, sdl2.SDL_PIXELFORMAT_RGBA8888, 0).contents
    sdl2.SDL_FreeSurface(surface_temp)

    return Image.from_SDL_Surface(surface)