我们使用以下构造函数创建了一个自定义表单finisher:
/**
* @var \TYPO3\CMS\Extbase\Persistence\Generic\PersistenceManager $persistenceManager
*/
protected $persistenceManager = null;
/**
* @var \[NAMESPACE]\[ExtName]\Domain\Repository\ArticleRepository $articleRepository
*/
protected $articleRepository = null;
public function __construct() {
parent::__construct();
$this->persistenceManager = GeneralUtility::makeInstance(\TYPO3\CMS\Extbase\Persistence\Generic\PersistenceManager::class);
$this->articleRepository = GeneralUtility::makeInstance(\[NAMESPACE]\[ExtName]\Domain\Repository\ArticleRepository::class);
}当表单几乎同时执行(延迟1-5秒测试)时,表单提交者中的一个将得到错误:
对于函数TYPO3\CMS\Extbase\Persistence\Repository::__construct(),0来说,
参数太少,在第3477行的path_to_docroot/httpdocs/typo3/sysext/core/Classes/Utility/GeneralUtility.php中传递,并且正好是预期的1
当它试图创建ArticleRepository的实例时,就会发生这种情况:
1:
TYPO3\CMS\Core\Utility\GeneralUtility::makeInstance('NAMESPACE[ExtName]\Domain\Repository\ArticleRepository')在path_to_docroot/httpdocs/typo3conf/ext/ext_name/Classes/Domain/Finishers/ImageGalleryFinisher.php第31行的
28 public function __construct() {
29 parent::__construct();
30 $this->persistenceManager = GeneralUtility::makeInstance(\TYPO3\CMS\Extbase\Persistence\Generic\PersistenceManager::class);
31 $this->articleRepository = GeneralUtility::makeInstance(\[NAMESPACE]\[ExtName]\Domain\Repository\ArticleRepository::class);
32 }2:
TYPO3\CMS\Extbase\Persistence\Repository->__construct()在path_to_docroot/httpdocs/typo3/sysext/core/Classes/Utility/GeneralUtility.php 3477行的
3473 return self::$container->get($className);
3474 }
3475
3476 // Create new instance and call constructor with parameters
3477 $instance = new $finalClassName(...$constructorArguments);
3478 // Register new singleton instance, but only if it is not a known PSR-11 container service
3479 if ($instance instanceof SingletonInterface && !(self::$container !== null && self::$container->has($className))) {
3480 self::$singletonInstances[$finalClassName] = $instance;
3481 }3(发生错误时):
path_to_docroot/httpdocs/typo3/sysext/extbase/Classes/Persistence/Repository.php第71行中的
67 * Constructs a new Repository
68 *
69 * @param \TYPO3\CMS\Extbase\Object\ObjectManagerInterface $objectManager
70 */
71 public function __construct(ObjectManagerInterface $objectManager)
72 {
73 $this->objectManager = $objectManager;
74 $this->objectType = ClassNamingUtility::translateRepositoryNameToModelName($this->getRepositoryClassName());
75 }另一个提交是没有问题地执行的。我们已经在一个分期环境中测试过这个。我的同事不能通过同时执行两个表单来在本地重新创建相同的错误(尽管他的执行速度可能比暂存环境更快)。
我重申,问题是同时执行终结者。但是为什么呢?这能防止吗?是否有可能将ObjectManagerInterface中继到此构造函数?
或者有人能看到另一个缺陷?或者这是核心的某个地方的错误?
我什么都找不到..。任何帮助或指示都将不胜感激,谢谢。
发布于 2021-11-23 15:01:52
在尝试了许多不同的事情之后,我终于找到了解决方案。
使用inject注释的:
/**
* @var PersistenceManager $persistenceManager
* @\TYPO3\CMS\Extbase\Annotation\Inject
*/
protected $persistenceManager = null;
/**
* @var ArticleRepository $articleRepository
* @\TYPO3\CMS\Extbase\Annotation\Inject
*/
protected $articleRepository = null;然后可以删除构造函数,它可以同时执行。干杯!
https://stackoverflow.com/questions/70079597
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