如何匹配Python3中字符和空格后面的字符串？

Question

我有以下字符串：

'- Submission GMV / return finance027110/06 Abdul Rahman -26,00- Submission GMV / return finance02432548/08 Michael Scott -56,47- GMV success. 452630/10/21 Lehazq998890/92 +60,00'

如何将值返回为：

[['- Submission PVT / return finance027110/06 Abdul Rahman','-26,00'],
 ['- Submission LTD / return finance02432548/08 Michael Scott','-56,47'],
 ['- GMV success. 452630/10/21 Lehazq998890/92', '+60,00']]

我正在循环进入多个输入。因此，输出行的计数在每次迭代中都不同。但分裂模式保持不变。

Answer 1

通过将re.findall与两个捕获组一起使用，您的需求很容易获得：

inp = "- Submission GMV / return finance027110/06 Abdul Rahman -26,00- Submission GMV / return finance02432548/08 Michael Scott -56,47- GMV success. 452630/10/21 Lehazq998890/92 +60,00"
matches = re.findall(r'(-.*?) ([+-]\d+(?:,\d+)?)', inp)
print(matches)

这些指纹：

[('- Submission GMV / return finance027110/06 Abdul Rahman', '-26,00'),
 ('- Submission GMV / return finance02432548/08 Michael Scott', '-56,47'),
 ('- GMV success. 452630/10/21 Lehazq998890/92', '+60,00')]

Answer 2

试试像这样的data.split('- ')[1:]