Javascript中不适用于RegEx的unicode标志

Question

我的代码无法检测操作符以及非英语字符的用法：

const OPERATOR_REGEX = new RegExp(
  /(?!\B"[^"|“|”]*)\b(and|or|not|exclude)(?=.*[\s])\b(?![^"|“|”]*"\B)/,
  'giu'
);

const query1 = '(Java or "化粧" or 化粧品)';
const query2 = '(Java or 化粧 or 化粧品)';

console.log(query1.split(OPERATOR_REGEX));
console.log(query2.split(OPERATOR_REGEX));

https://codepen.io/thewebtud/pen/vYraavd?editors=1111

相同的代码成功地使用unicode标志：https://regex101.com/r/FC84BH/1检测regex101.com上的所有操作符。

如何为JS修复这个问题？

Answer 1

记住

• \b (word boundary)可以写成(?:(?<=^)(?=\w)|(?<=\w)(?=$)|(?<=\W)(?=\w)|(?<=\w)(?=\W)) and
• \B (non-word boundary)可以写成(?:(?<=^)(?=\W)|(?<=\W)(?=$)|(?<=\W)(?=\W)|(?<=\w)(?=\w))

支持Unicode的\w模式是[\p{Alphabetic}\p{Mark}\p{Decimal_Number}\p{Connector_Punctuation}\p{Join_Control}] (参见)，下面是ECMAScript 2018+解决方案：

​

const w = String.raw`[\p{Alphabetic}\p{Mark}\p{Decimal_Number}\p{Connector_Punctuation}\p{Join_Control}]`;
const nw = String.raw`[^\p{Alphabetic}\p{Mark}\p{Decimal_Number}\p{Connector_Punctuation}\p{Join_Control}]`;
const uwb = String.raw`(?:(?<=^)(?=${w})|(?<=${w})(?=$)|(?<=${nw})(?=${w})|(?<=${w})(?=${nw}))`;
const unwb = String.raw`(?:(?<=^)(?=${nw})|(?<=${nw})(?=$)|(?<=${nw})(?=${nw})|(?<=${w})(?=${w}))`;

const OPERATOR_REGEX = new RegExp(
  String.raw`(?!${unwb}"[^"“”]*)${uwb}(and|or|not|exclude)(?=.*\s)${uwb}(?![^"“”]*"${unwb})`,
  'giu'
);

const query1 = '(Java or "化粧" or 化粧品)';
const query2 = '(Java or 化粧 or 化粧品)';

console.log(query1.split(OPERATOR_REGEX));
console.log(query2.split(OPERATOR_REGEX));

​