我的for循环不允许我增加迭代器变量-Python2.7

Question

大家好，

新来的。我正在编写这个函数，它在技术上是可行的，但我仍然希望"i“在每个循环上增加1，但它不会让它增加。每个循环只需要一个参数。如果我更改变量名"i“-> "it"，则won语句甚至不会开始。

**提前感谢你对此保持冷静！**

`

def solution(s):
    i = 0
    m = ""
    braille = {
" " : "000000",
"^" : "000001",
"a" :   "100000",
"b" :   "110000",
"c" :   "100100",
"d" :   "100110",
"e" :   "100010",
"f" :   "110100",
"g" :   "110110",
"h" :   "110010",
"i" :   "010100",
"j" :   "010110",
"k" :   "101000",
"l" :   "111000",
"m" :   "101100",
"n" :   "101110",
"o" :   "101010",
"p" :   "111100",
"q" :   "111110",
"r" :   "111010",
"s" :   "011100",
"t" :   "011110",
"u" :   "101001",
"v" :   "111001",
"w" :   "010111",
"x" :   "101101",
"y" :   "101111",
"z" :   "101011"
}

    while i < len(s):

        for i in s:
            if i.isupper() == True:
                m += braille["^"]+braille[i.lower()]
            else:
            m += braille[i]
    print(m)

solution("hello")

`

它可以工作，但是迭代器变量不会在每个循环中增加。

Answer 1

我不确定这是否是你想打印的，但让我试试看：(我假设你想打印盲文图案)

首先，您犯了错误，在while循环中使用i作为索引，但在s中也使用i作为索引。

然后，您也无法在while循环中增加i。

还为每一个新的while循环添加换行符：

这是我的代码(请检查)：

def solution(s):
    i = 0
    m = ""
    braille = {
    " " : "000000",
    "^" : "000001",
    "a" :   "100000",
    "b" :   "110000",
    "c" :   "100100",
    "d" :   "100110",
    "e" :   "100010",
    "f" :   "110100",
    "g" :   "110110",
    "h" :   "110010",
    "i" :   "010100",
    "j" :   "010110",
    "k" :   "101000",
    "l" :   "111000",
    "m" :   "101100",
    "n" :   "101110",
    "o" :   "101010",
    "p" :   "111100",
    "q" :   "111110",
    "r" :   "111010",
    "s" :   "011100",
    "t" :   "011110",
    "u" :   "101001",
    "v" :   "111001",
    "w" :   "010111",
    "x" :   "101101",
    "y" :   "101111",
    "z" :   "101011"
    }

    while i < len(s):
        m += '\n' # add new line for the next part of the print
        for k in s: # change i to k as index in for loop
            if k.isupper() == True:
                m += braille["^"]+braille[k.lower()]
            else:
                m += braille[k]
        i += 1 # increment the i for the while loop
    
    print(m)

solution("hello")

我的跑步结果：

110010100010111000111000101010
110010100010111000111000101010
110010100010111000111000101010
110010100010111000111000101010
110010100010111000111000101010

这是你想打印的图案吗？

如果你只想打印一次盲文图案，那么你就不需要then循环了。for循环就足够了：

def solution(s):
    i = 0
    m = ""
    braille = {
    " " : "000000",
    "^" : "000001",
    "a" :   "100000",
    "b" :   "110000",
    "c" :   "100100",
    "d" :   "100110",
    "e" :   "100010",
    "f" :   "110100",
    "g" :   "110110",
    "h" :   "110010",
    "i" :   "010100",
    "j" :   "010110",
    "k" :   "101000",
    "l" :   "111000",
    "m" :   "101100",
    "n" :   "101110",
    "o" :   "101010",
    "p" :   "111100",
    "q" :   "111110",
    "r" :   "111010",
    "s" :   "011100",
    "t" :   "011110",
    "u" :   "101001",
    "v" :   "111001",
    "w" :   "010111",
    "x" :   "101101",
    "y" :   "101111",
    "z" :   "101011"
    }

    
    for k in s: # change i to k as index in for loop
        if k.isupper() == True:
            m += braille["^"]+braille[k.lower()]
        else:
            m += braille[k]
        
    
    print(m)

solution("hello")

然后输出将是：

110010100010111000111000101010