如何在与按钮交互后编辑/删除斜杠命令消息(不和py disnake api包装器)

Question

下面是一个简单的硬币翻转例子，我为这个问题做了一个简单的例子:有任何方法可以-edit原始的斜杠命令消息和硬币翻转的结果，以去掉按钮-delete，原始斜杠命令消息

class CoinFlipButtons(disnake.ui.View):
    def __init__(self):
       super().__init__(timeout=60)
      
    @bot.slash_command(description="starts coin flip game")
    async def coinflip(inter):
        await inter.response.send_message("Coin has been flipped what shall you choose?", view=CoinFlipButtons())
        

    @disnake.ui.button(label="Heads", style=ButtonStyle.green)
    async def first_button(self, button: disnake.ui.Button, inter: disnake.MessageInteraction):
        coin = random.randrange(1,2)
        if coin == 1:
            coin = "heads"
        else: 
            coin = "tails"
        if coin == "heads":
            await inter.response.send_message(content=f"You were correct! It was {coin}")
        else:
            await inter.response.send_message(content=f"Oh no! The coin was {coin}")


    @disnake.ui.button(label="Tails", style=ButtonStyle.red)
    async def second_button(self, button: disnake.ui.Button, inter: disnake.MessageInteraction):
        coin = random.randrange(1,2)
        if coin == 1:
            coin = "heads"
        else: 
            coin = "tails"
        if coin == "tails":
            await inter.response.send_message(f"You were correct! It was {coin}")
        else:
            await inter.response.send_message(f"Oh no! The coin was {coin}")

我尝试在文档中搜索编辑、原始响应、消息函数或其他类似的东西，但是这些函数都无法工作，因为当我向按钮发送新的响应时，交互是重新定义的，这是im遇到困难的地方，因为我想在按钮交互之后编辑/删除斜杠命令交互。

Answer 1

编辑：

await inter.response.edit_message()