在if-语句中函数之前未执行的代码

Question

我正在尝试运行一个if-语句，一旦选择了数字1到7，相应的财务数据就会被上传为代码。但是，在我的if语句中，导入数据的代码没有运行，它直接跳转到函数main_2()。函数main_2()和导入金融数据的代码都是作为结束符，然后保持‘关闭’单独运行完美，但是当放在if语句中时，main_2()只运行。我正在使用spyder运行这个程序。

import yahoofinance as yf 
def main_():
    print("Choose dataset")
    print("1.Amazon \n2.Apple \n3.Cisco \n4.Meta \n5.Microsoft \n6.Qualcomm \n7.Starbucks")
    choice = input("Please choose option: ")
    if choice == '1':
        ticker = yf.Ticker('AMZN')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    if choice == '2':
        ticker = yf.Ticker('AAPL')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    if choice == '3':
        ticker = yf.Ticker('CSCO')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    if choice == '4':
        ticker = yf.Ticker('META')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    if choice == '5':
        ticker = yf.Ticker('MSFT')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    if choice == '6':
        ticker = yf.Ticker('QCOM')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    if choice == '7':
        ticker = yf.Ticker('SBUX')
        ticker = ticker.history(period="5y")
        ticker_ = ticker[['Close']]
        print('1.Descriptive Analytics \n2.Visual Analysis \n3.Predictive Analysis')
        main_2()
    
def main_2():        
    typ = input('Choose type of analysis:')
    if typ == '1':
        print(ticker_.describe())
        main_()
    elif typ == '2':
        print('1.Moving Averages \n2.Scatter plot \n3.Trend Lines')
        main_3()
    elif typ == '3':
        predictive()
        main_()
def main_3(): 
    graphical = input('Choose sort of graphical analysis:')
    if graphical == '1':
        moving_averages()
        main_4()
    elif graphical == '2':
        scatter_plot()
        main_4()
    elif graphical == '3':
        trend_line()
        main_4()
def main_4():
    print('1.Return to Main Menu \n2.Quit')
    option = input('Choose option:')
    if option == '1':
        main_()
    elif option == '2':
        quit()

main()

Answer 1

您应该有以下错误：NameError: name 'ticker' is not defined

调用main_2作为参数：main_2(ticker)，为了测试它，您可以在main_2中打印ticker以查看它是否正常工作。

def main_2(ticker): 
    print(ticker)